The expression al(b - c) + d] is equivalent to:

ab + ac + ad

ab - ac + d

ab - ac + ad

ab-c+d

a -c+d

The expression given is \( al(b - c) + d \). Let's simplify it step by step:

1. Distribute \( al \) to both \( b \) and \( c \):
   \[
   al(b - c) = al \cdot b - al \cdot c = ab - ac
   \]

2. Now add \( d \) to the result:
   \[
   ab - ac + d
   \]

So, the expression \( al(b - c) + d \) is equivalent to:

**\( ab - ac + d \)**.

Would you like to see more details or have any questions?

Here are 5 related questions to consider:

1. How would the expression change if \( d \) was multiplied by \( a \) as well?
2. What happens if you substitute specific numbers for \( a \), \( b \), \( c \), and \( d \)?
3. Can you factor the expression \( ab - ac + d \) any further?
4. How does the distributive property apply in this situation?
5. What is the result if \( b \) and \( c \) are equal?

**Tip:** Always be careful with the signs when distributing terms across parentheses; this is where most mistakes happen.

Learn how to simplify the algebraic expression al(b - c) + d step-by-step. This problem involves applying the distributive property in algebra and simplifying expressions. Suitable for students in Grades 7-9.

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