Math Problem Statement

The expression al(b - c) + d] is equivalent to:

ab + ac + ad

ab - ac + d

ab - ac + ad

ab-c+d

a -c+d

Solution

The expression given is al(bc)+dal(b - c) + d. Let's simplify it step by step:

  1. Distribute alal to both bb and cc: al(bc)=albalc=abacal(b - c) = al \cdot b - al \cdot c = ab - ac

  2. Now add dd to the result: abac+dab - ac + d

So, the expression al(bc)+dal(b - c) + d is equivalent to:

abac+dab - ac + d.

Would you like to see more details or have any questions?

Here are 5 related questions to consider:

  1. How would the expression change if dd was multiplied by aa as well?
  2. What happens if you substitute specific numbers for aa, bb, cc, and dd?
  3. Can you factor the expression abac+dab - ac + d any further?
  4. How does the distributive property apply in this situation?
  5. What is the result if bb and cc are equal?

Tip: Always be careful with the signs when distributing terms across parentheses; this is where most mistakes happen.

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Math Problem Analysis

Mathematical Concepts

Algebra
Distributive Property

Formulas

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Theorems

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Suitable Grade Level

Grades 7-9