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The image contains six word problems related to simple interest rates. I will walk you through solving them one by one.

### Simple Interest Formula:
The formula to calculate simple interest is:
\[
I = P \times r \times t
\]
Where:
- \( I \) = Interest
- \( P \) = Principal amount
- \( r \) = Interest rate (in decimal form)
- \( t \) = Time (in years)

### Problem 1:
**How much interest is earned on ₱6,200 at 4% for one year?**

Using the simple interest formula:
\[
I = 6200 \times 0.04 \times 1
\]
\[
I = 248
\]
So, the interest earned is **₱248**.

---

### Problem 2:
**What was the interest rate if your balance on an investment of ₱27,750 at the end of six years is ₱41,070?**

Here, we need to find the interest rate (\( r \)). The total balance is ₱41,070, which includes both the principal and the interest. First, calculate the interest:
\[
I = 41070 - 27750 = 13,320
\]
Now, rearrange the formula to solve for \( r \):
\[
I = P \times r \times t \quad \Rightarrow \quad r = \frac{I}{P \times t}
\]
\[
r = \frac{13320}{27750 \times 6} \approx 0.08
\]
So, the interest rate is **8%**.

---

### Problem 3:
**At what rate was an investment made that obtains ₱2,520 on ₱10,500 over four years?**

Here, we also need to find \( r \). Using the same rearrangement:
\[
I = 2520, \, P = 10500, \, t = 4
\]
\[
r = \frac{2520}{10500 \times 4} = 0.06
\]
So, the rate is **6%**.

---

### Problem 4:
**If a loan is taken out for ₱15,900 at 9% and costs ₱8,586, how long was the loan for?**

We need to find the time (\( t \)). Using the simple interest formula and rearranging for \( t \):
\[
I = 8586, \, P = 15900, \, r = 0.09
\]
\[
t = \frac{I}{P \times r} = \frac{8586}{15900 \times 0.09} \approx 6
\]
So, the loan was for **6 years**.

---

### Problem 5:
**A bank is offering 3.5% simple interest on a savings account. If you deposit ₱10,555, how much interest will you earn in two years?**

Using the formula:
\[
P = 10555, \, r = 0.035, \, t = 2
\]
\[
I = 10555 \times 0.035 \times 2 = 739
\]
So, the interest earned is **₱739**.

---

### Problem 6:
**If you borrow ₱75,000 for two and a half years at an interest rate of 9.5%, what is the maturity value of the loan?**

The maturity value \( A \) is the sum of the principal and the interest:
\[
I = P \times r \times t = 75000 \times 0.095 \times 2.5 = 17812.5
\]
\[
A = P + I = 75000 + 17812.5 = 92812.5
\]
So, the maturity value is **₱92,812.50**.

---

Let me know if you need further details on any of these or have questions! Here are five related questions for further practice:

1. What would be the interest earned on a loan of ₱5,000 at 6% interest for 3 years?
2. How long will it take to double an investment of ₱20,000 at an interest rate of 5%?
3. If you deposit ₱12,000 at 4.5% interest, how much will you have in 5 years?
4. How much would you earn in interest if you borrowed ₱50,000 at 7% for 10 years?
5. What is the maturity value of a ₱15,000 loan after 3 years at 8%?

**Tip:** Always convert percentage rates to decimals (by dividing by 100) before using them in the formula.

How much interest is earned on ₱6,200 at 4% for one year?

Learn how to calculate the simple interest on ₱6,200 at an interest rate of 4% for one year. This problem helps students understand basic percentage calculations and the simple interest formula.

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