Math Problem Statement

An object is attached to a coiled spring. It is pulled down a distance of 3 inches from its equilibrium position, then released.

If the time for one complete oscillation is 7 seconds, find the equation of the simple harmonic motion.

A.) s left parenthesis t right parenthesis equals 3 sin open parentheses fraction numerator 2 straight pi over denominator 7 end fraction t close parentheses

B.) s left parenthesis t right parenthesis equals 3 cos open parentheses fraction numerator 2 straight pi over denominator 7 end fraction t close parentheses

C.) s left parenthesis t right parenthesis equals short dash 3 cos open parentheses fraction numerator 2 straight pi over denominator 7 end fraction t close parentheses

D.) s left parenthesis t right parenthesis equals short dash 3 sin open parentheses fraction numerator 2 straight pi over denominator 7 end fraction t close parentheses

Solution

To find the equation of the simple harmonic motion, let's first recall the general form for simple harmonic motion (SHM):

s(t)=Asin(ωt+ϕ)s(t) = A \sin\left(\omega t + \phi\right) or s(t)=Acos(ωt+ϕ)s(t) = A \cos\left(\omega t + \phi\right) Where:

  • AA is the amplitude (the maximum displacement from equilibrium),
  • ω\omega is the angular frequency (in radians per second),
  • ϕ\phi is the phase constant (which determines the initial conditions).

Step 1: Identify Given Information

  • The amplitude AA is the maximum displacement from the equilibrium position. The object is pulled down 3 inches from equilibrium, so: A=3inchesA = 3 \, \text{inches}
  • The time for one complete oscillation (the period TT) is 7 seconds: T=7secondsT = 7 \, \text{seconds}
  • The angular frequency ω\omega is related to the period by the formula: ω=2πT\omega = \frac{2\pi}{T} Substituting the given value for TT: ω=2π7\omega = \frac{2\pi}{7}

Step 2: Analyze the Initial Conditions

The problem states that the object is initially pulled downward (so the displacement is negative) and then released. This suggests that at t=0t = 0, the displacement s(0)=3s(0) = -3 inches. This is a typical starting condition for a cosine function, which starts at its maximum or minimum value.

Thus, the equation should be in the cosine form, with a negative amplitude because the initial displacement is downward.

Step 3: Write the Equation

The equation for simple harmonic motion, given that the amplitude is 3 inches, the angular frequency is 2π7\frac{2\pi}{7}, and the initial displacement is negative, is:

s(t)=3cos(2π7t)s(t) = -3 \cos\left(\frac{2\pi}{7} t \right)

This matches the form of the equation in option C.

Final Answer:

C.) s(t)=3cos(2π7t)s(t) = -3 \cos\left(\frac{2\pi}{7} t \right)


Would you like further clarification on how I derived the solution, or is there another concept you'd like to explore? Here are a few related questions to deepen the understanding:

  1. What would the phase constant ϕ\phi be if the displacement were +3+3 inches instead of 3-3?
  2. How do you calculate the velocity and acceleration in simple harmonic motion?
  3. What is the relationship between angular frequency ω\omega and frequency ff?
  4. How do you find the period of a mass-spring system using Hooke's Law?
  5. What happens to the motion if the object is displaced more than the amplitude?

Tip: The cosine function is typically used when an object starts at its maximum displacement, while the sine function is used when the object starts from the equilibrium position moving in the positive direction.

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Math Problem Analysis

Mathematical Concepts

Simple Harmonic Motion
Trigonometric Functions
Angular Frequency
Amplitude

Formulas

s(t) = A cos(ωt + φ)
ω = 2π / T

Theorems

Simple Harmonic Motion Equation
Relation between Period and Angular Frequency

Suitable Grade Level

Grades 11-12