Math Problem Statement

Write the following series in sigma notation. 4, plus, 13, plus, 22, plus, 31 4+13+22+31

Solution

The given series is:

4+13+22+314 + 13 + 22 + 31

This is an arithmetic sequence where the first term a1=4a_1 = 4 and the common difference d=9d = 9 (since 134=913 - 4 = 9, 2213=922 - 13 = 9, and so on).

We can express the general term of an arithmetic sequence as:

an=a1+(n1)da_n = a_1 + (n - 1) \cdot d

Substituting the values of a1=4a_1 = 4 and d=9d = 9:

an=4+(n1)9=9n5a_n = 4 + (n - 1) \cdot 9 = 9n - 5

Thus, the general term is an=9n5a_n = 9n - 5, and the sequence consists of 4 terms. Therefore, the sum can be written in sigma notation as:

n=14(9n5)\sum_{n=1}^{4} (9n - 5)

Would you like more details on sigma notation or how to handle other sequences?

Here are some related questions:

  1. How do you find the sum of an arithmetic series?
  2. What is the difference between arithmetic and geometric series?
  3. Can sigma notation be used for non-arithmetic series?
  4. How would the series change if the common difference were different?
  5. What are the key properties of sigma notation?

Tip: When writing in sigma notation, always check the pattern of the sequence first—whether it's arithmetic, geometric, or something else!

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Sigma Notation
Series

Formulas

General term of an arithmetic sequence: a_n = a_1 + (n - 1) * d
Sum of an arithmetic series in sigma notation: ∑_{n=1}^{N} (a_n)

Theorems

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Suitable Grade Level

Grades 9-10