Math Problem Statement

Find the shortest path from E to F in the given graph.

Solution

To find the shortest path from vertex EE to vertex FF in the given graph, we can apply Dijkstra's algorithm or simply inspect the paths manually since the graph is small.

Step 1: List all possible paths from EE to FF:

  1. EACFE \rightarrow A \rightarrow C \rightarrow F
  2. EADFE \rightarrow A \rightarrow D \rightarrow F
  3. EBDFE \rightarrow B \rightarrow D \rightarrow F
  4. EBCFE \rightarrow B \rightarrow C \rightarrow F
  5. EDFE \rightarrow D \rightarrow F

Step 2: Calculate the total weights for each path:

  1. EACF:3+6+6=15E \rightarrow A \rightarrow C \rightarrow F: 3 + 6 + 6 = 15
  2. EADF:3+1+3=7E \rightarrow A \rightarrow D \rightarrow F: 3 + 1 + 3 = 7
  3. EBDF:7+4+3=14E \rightarrow B \rightarrow D \rightarrow F: 7 + 4 + 3 = 14
  4. EBCF:7+1+6=14E \rightarrow B \rightarrow C \rightarrow F: 7 + 1 + 6 = 14
  5. EDF:7+3=10E \rightarrow D \rightarrow F: 7 + 3 = 10

Step 3: Identify the shortest path:

  • The shortest path is EADFE \rightarrow A \rightarrow D \rightarrow F with a total weight of 7.

Thus, the shortest path from EE to FF is EADFE \rightarrow A \rightarrow D \rightarrow F with a distance of 7.

Would you like to explore more details or have any further questions?

Here are some related questions:

  1. What is Dijkstra's algorithm, and how does it work?
  2. How would the shortest path change if the weight between EE and BB was reduced?
  3. Can you explain why some paths are longer than others?
  4. How does this problem relate to real-world applications of shortest path algorithms?
  5. What if we were looking for the longest path instead of the shortest?

Tip: When solving shortest path problems, ensure you evaluate all possible paths to avoid missing the optimal solution.

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Math Problem Analysis

Mathematical Concepts

Graph Theory
Shortest Path Problem

Formulas

Summing the edge weights for paths
Dijkstra’s Algorithm

Theorems

Shortest path algorithm (Dijkstra’s)

Suitable Grade Level

Grades 10-12