The given expression \((A - B)' \cap U\) involves set operations, including the complement and intersection of sets. Let's break it down step by step:

1. **Expression Breakdown:**
   - \(A - B\): This represents the **difference** between sets \(A\) and \(B\). It contains all the elements that are in \(A\) but not in \(B\).
   - \((A - B)'\): This is the **complement** of the set \(A - B\). It includes all elements that are **not** in \(A - B\).
   - \(\cap U\): This indicates the **intersection** with the universal set \(U\). The intersection of any set with the universal set \(U\) is simply the set itself because \(U\) contains all possible elements in the context.

2. **Solution:**
   - The complement \((A - B)'\) includes all elements **not** in \(A - B\). Therefore, \((A - B)'\) would be the set of elements that are either in \(B\) or not in \(A\).
   - The intersection of \((A - B)'\) with \(U\) is simply \((A - B)'\) itself since the universal set \(U\) contains all elements under consideration.

So, \((A - B)' \cap U = (A - B)'\).

### Final Answer:
\[
(A - B)' \cap U = (A - B)'
\]

Would you like more details or have any questions?  

Here are five related questions to explore further:
1. What is the complement of a set with respect to the universal set \(U\)?
2. How do you calculate the difference between two sets?
3. Can the universal set \(U\) ever be empty?
4. How does the intersection of sets differ from the union?
5. What happens if \(A\) is a subset of \(B\)?

**Tip:** When working with set operations, always consider the universal set \(U\) to understand the context of complements and intersections properly.

Understand how to solve the set operation expression (A - B)' ∩ U. Learn about set difference, complement, and intersection with the universal set. This problem involves key concepts from set theory, including De Morgan's Laws and the complement of sets. Suitable for high school students in Grades 9-12.

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