Math Problem Statement

If X = {1}, Y = {2, 3}, Z = {2, 5, 6}, represent the sets of X, Y, Z with Venn diagram, then find: (a) X × Y, (b) Y × Z, (c) X × Z U (Y × Z), (d) Y², and other Cartesian product operations.

Solution

The exercise in the image asks to represent the sets X={1},Y={2,3},Z={2,5,6}X = \{1\}, Y = \{2, 3\}, Z = \{2, 5, 6\} with a Venn diagram and then solve the following problems:

  1. X×YX \times Y
  2. Y×ZY \times Z
  3. X×(YZ)X \times (Y \cap Z)
  4. (X×Y)(X×Z)(X \times Y) \cap (X \times Z)
  5. (ZY)×(XY)(Z - Y) \times (X \cup Y)

Let's go step by step:

1. X×YX \times Y

This is the Cartesian product of sets XX and YY, which means all possible ordered pairs where the first element is from XX and the second element is from YY.

Since X={1}X = \{1\} and Y={2,3}Y = \{2, 3\}, we get: X×Y={(1,2),(1,3)}X \times Y = \{ (1, 2), (1, 3) \}

2. Y×ZY \times Z

Similarly, the Cartesian product Y×ZY \times Z gives all ordered pairs with the first element from YY and the second from ZZ.

With Y={2,3}Y = \{2, 3\} and Z={2,5,6}Z = \{2, 5, 6\}, we get: Y×Z={(2,2),(2,5),(2,6),(3,2),(3,5),(3,6)}Y \times Z = \{ (2, 2), (2, 5), (2, 6), (3, 2), (3, 5), (3, 6) \}

3. X×(YZ)X \times (Y \cap Z)

Now, we need to find the intersection YZY \cap Z, which is the set of elements common to both YY and ZZ.

Since Y={2,3}Y = \{2, 3\} and Z={2,5,6}Z = \{2, 5, 6\}, we have: YZ={2}Y \cap Z = \{2\} Thus, X×(YZ)=X×{2}={(1,2)}X \times (Y \cap Z) = X \times \{2\} = \{ (1, 2) \}.

4. (X×Y)(X×Z)(X \times Y) \cap (X \times Z)

First, we calculate X×ZX \times Z: X×Z={(1,2),(1,5),(1,6)}X \times Z = \{ (1, 2), (1, 5), (1, 6) \} Now, we take the intersection of X×YX \times Y and X×ZX \times Z. These two sets are: X×Y={(1,2),(1,3)}X \times Y = \{ (1, 2), (1, 3) \} X×Z={(1,2),(1,5),(1,6)}X \times Z = \{ (1, 2), (1, 5), (1, 6) \} The only common element is (1,2)(1, 2), so: (X×Y)(X×Z)={(1,2)}(X \times Y) \cap (X \times Z) = \{ (1, 2) \}

5. (ZY)×(XY)(Z - Y) \times (X \cup Y)

First, we calculate ZYZ - Y, which is the set difference (elements in ZZ that are not in YY).

Since Z={2,5,6}Z = \{2, 5, 6\} and Y={2,3}Y = \{2, 3\}, we have: ZY={5,6}Z - Y = \{5, 6\}

Next, we compute XYX \cup Y, the union of XX and YY, which includes all elements in either set: XY={1,2,3}X \cup Y = \{1, 2, 3\}

Finally, we find the Cartesian product: (ZY)×(XY)={(5,1),(5,2),(5,3),(6,1),(6,2),(6,3)}(Z - Y) \times (X \cup Y) = \{ (5, 1), (5, 2), (5, 3), (6, 1), (6, 2), (6, 3) \}


Would you like more details on any of these steps? Here are five questions that expand on this problem:

  1. What are the key differences between union, intersection, and Cartesian product of sets?
  2. How would the solution change if one of the sets was empty?
  3. Can the Cartesian product be applied to more than two sets simultaneously?
  4. How would we visualize these set relationships using a Venn diagram?
  5. How does set difference differ from symmetric difference?

Tip: When working with sets, it's helpful to first compute any intersections or differences before applying operations like Cartesian products to simplify the problem.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Cartesian Product
Union
Intersection
Set Difference

Formulas

Cartesian product X × Y: All ordered pairs (x, y) where x ∈ X and y ∈ Y.
Intersection Y ∩ Z: Elements common to both sets.
Union X ∪ Y: Elements in either X or Y.

Theorems

Basic Set Theory
Cartesian Product Rules
Set Intersection and Union Properties

Suitable Grade Level

Grade 9-11