Math Problem Statement

CCS 1501 TUTORIAL_SHEET_1__SET_THEORY.pdf

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solve from question 8

Solution

Let's address question 8 from the tutorial sheet:


Given:

  • The universal set E=RE = \mathbb{R} (set of real numbers).
  • The sets are defined as:
    • X={x3<x<6}X = \{ x \mid 3 < x < 6 \}
    • Y={x5x7}Y = \{ x \mid 5 \leq x \leq 7 \}
    • Z={0,1,2,3}Z = \{ 0, 1, 2, 3 \}

You are asked to find:

(i) XYX \cap Y
(ii) XZX' \cap Z
(iii) (XY)Z(X \cap Y) \cap Z
(iv) X(YZ)X \cap (Y \cap Z)


Step-by-step Solutions:

(i) XYX \cap Y

We are given:

  • X={x3<x<6}X = \{ x \mid 3 < x < 6 \}
  • Y={x5x7}Y = \{ x \mid 5 \leq x \leq 7 \}

The intersection XYX \cap Y represents all elements that belong to both sets.

  • X={3<x<6}X = \{ 3 < x < 6 \}, so X=(3,6)X = (3, 6).
  • Y={5x7}Y = \{ 5 \leq x \leq 7 \}, so Y=[5,7]Y = [5, 7].

The intersection of these two sets is the overlap of the intervals:

  • XY=[5,6)X \cap Y = [5, 6).

(ii) XZX' \cap Z

XX' represents the complement of XX in R\mathbb{R}, which means all real numbers except those between 3 and 6. So, XX' is:

  • X=(,3][6,)X' = (-\infty, 3] \cup [6, \infty).

We are given:

  • Z={0,1,2,3}Z = \{ 0, 1, 2, 3 \}.

Now, the intersection XZX' \cap Z represents all elements in ZZ that are not in XX, i.e., all elements of ZZ that are less than or equal to 3 or greater than or equal to 6.

  • XZ={0,1,2,3}X' \cap Z = \{ 0, 1, 2, 3 \}.

(iii) (XY)Z(X \cap Y) \cap Z

From part (i), we found that XY=[5,6)X \cap Y = [5, 6). Now, we intersect this with Z={0,1,2,3}Z = \{ 0, 1, 2, 3 \}:

  • (XY)Z={0,1,2,3}[5,6)=(X \cap Y) \cap Z = \{ 0, 1, 2, 3 \} \cap [5, 6) = \emptyset.

Thus, the result is an empty set:

  • (XY)Z=(X \cap Y) \cap Z = \emptyset.

(iv) X(YZ)X \cap (Y \cap Z)

First, we find the intersection of YY and ZZ:

  • Y=[5,7]Y = [5, 7]
  • Z={0,1,2,3}Z = \{ 0, 1, 2, 3 \}

The intersection YZY \cap Z is empty since there are no elements in ZZ that are between 5 and 7.

Thus:

  • YZ=Y \cap Z = \emptyset.

Now, intersect this result with XX:

  • X=X \cap \emptyset = \emptyset.

So:

  • X(YZ)=X \cap (Y \cap Z) = \emptyset.

Summary of Results:

  • (i)XY=[5,6)(i) \, X \cap Y = [5, 6)
  • (ii)XZ={0,1,2,3}(ii) \, X' \cap Z = \{ 0, 1, 2, 3 \}
  • (iii)(XY)Z=(iii) \, (X \cap Y) \cap Z = \emptyset
  • (iv)X(YZ)=(iv) \, X \cap (Y \cap Z) = \emptyset

Let me know if you'd like further clarification or additional help with any other problems! Here are some related questions:

  1. How do you find the complement of a set in a specific universal set?
  2. What is the difference between the intersection and union of sets?
  3. How do you express the complement of an interval in set notation?
  4. Can the intersection of two sets ever be empty? When does this happen?
  5. How do you perform operations on sets when one set is defined by inequalities?

Tip: When working with set operations, always visualize the sets as intervals or number lines to better understand their relationships!

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Math Problem Analysis

Mathematical Concepts

Set Theory
Set Operations
Complement of a Set
Intersection of Sets

Formulas

X ∩ Y
X' ∩ Z
(X ∩ Y) ∩ Z
X ∩ (Y ∩ Z)

Theorems

De Morgan's Laws
Set Complement Properties
Intersection and Union of Sets

Suitable Grade Level

Grades 10-12