Math Problem Statement

Use the limit comparison test to determine whether the series ∑_(n=7)^∞ ((7n^3 - 7n^2 + 7) / (3 + 3n^4)) converges or diverges.

Solution

To determine the convergence or divergence of the series

n=77n37n2+73+3n4\sum_{n=7}^{\infty} \frac{7n^3 - 7n^2 + 7}{3 + 3n^4}

using the limit comparison test, we proceed as follows:

  1. Identify the Dominant Terms: We need to choose a simpler series bnb_n for comparison, typically by identifying the dominant terms in the numerator and denominator of an=7n37n2+73+3n4a_n = \frac{7n^3 - 7n^2 + 7}{3 + 3n^4} as nn \to \infty.

    • In the numerator 7n37n2+77n^3 - 7n^2 + 7, the term 7n37n^3 is dominant.
    • In the denominator 3+3n43 + 3n^4, the term 3n43n^4 is dominant.

    Therefore, as nn \to \infty, an7n33n4=73na_n \approx \frac{7n^3}{3n^4} = \frac{7}{3n}.

    Thus, we choose bn=1nb_n = \frac{1}{n}, which is a divergent pp-series (since 1n\sum \frac{1}{n} diverges).

  2. Apply the Limit Comparison Test: According to the limit comparison test, we compute

    limnanbn=limn7n37n2+73+3n41n=limnn(7n37n2+7)3+3n4.\lim_{n \to \infty} \frac{a_n}{b_n} = \lim_{n \to \infty} \frac{\frac{7n^3 - 7n^2 + 7}{3 + 3n^4}}{\frac{1}{n}} = \lim_{n \to \infty} \frac{n(7n^3 - 7n^2 + 7)}{3 + 3n^4}.

  3. Simplify the Expression: Expanding this,

    limn7n47n3+7n3+3n4.\lim_{n \to \infty} \frac{7n^4 - 7n^3 + 7n}{3 + 3n^4}.

    Dividing both the numerator and the denominator by n4n^4 to simplify, we get

    limn77n+7n33n4+3=73.\lim_{n \to \infty} \frac{7 - \frac{7}{n} + \frac{7}{n^3}}{\frac{3}{n^4} + 3} = \frac{7}{3}.

  4. Interpret the Result: The limit is a positive finite constant (73\frac{7}{3}), so by the limit comparison test, an\sum a_n and bn\sum b_n will either both converge or both diverge.

Since 1n\sum \frac{1}{n} diverges, it follows that an\sum a_n also diverges.

Conclusion

The series n=77n37n2+73+3n4\sum_{n=7}^{\infty} \frac{7n^3 - 7n^2 + 7}{3 + 3n^4} diverges.

Would you like a more detailed breakdown of any steps?

Here are 5 related questions to explore further:

  1. How does the limit comparison test differ from the direct comparison test?
  2. What are pp-series, and why does 1n\sum \frac{1}{n} diverge?
  3. Can the ratio test be used to determine convergence for this series?
  4. What other series tests could be applied to this series, if any?
  5. How would the solution change if the numerator and denominator terms were different?

Tip: In the limit comparison test, always choose a comparison term that matches the behavior of the dominant terms in ana_n as nn \to \infty.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Limit Comparison Test
Asymptotic Analysis
Dominant Term Approximation

Formulas

Limit Comparison Test: lim (n→∞) (a_n / b_n)
Dominant Term Approximation: a_n ≈ 7 / (3n) for large n

Theorems

Limit Comparison Test

Suitable Grade Level

Undergraduate Calculus