Math Problem Statement

If aₙ ≥ 0 and ∑ aₙ² is convergent, then ∑ (aₙ / n) is: (a) convergent (b) divergent (c) convergent and divergent both (d) none of these

Solution

To determine whether n=1ann\sum_{n=1}^\infty \frac{a_n}{n} is convergent, let's analyze the conditions:

  1. Given:

    • an0a_n \geq 0, i.e., ana_n is non-negative.
    • n=1an2\sum_{n=1}^\infty a_n^2 is convergent.

    This means that the series of squares of the ana_n terms is convergent.

  2. To Test:

    • Is n=1ann\sum_{n=1}^\infty \frac{a_n}{n} convergent?

Key Concepts:

  • Since an2a_n^2 is convergent, it follows by the Cauchy-Schwarz inequality (or other relevant tests) that ana_n behaves sufficiently small as nn \to \infty, particularly that it decays at a certain rate.
  • A comparison with 1n\frac{1}{n}-terms arises naturally.

Applying the Cauchy-Schwarz Inequality

The Cauchy-Schwarz inequality for two sequences {an}\{a_n\} and {bn}\{b_n\} states:
(n=1anbn)2(n=1an2)(n=1bn2).\left( \sum_{n=1}^\infty a_n b_n \right)^2 \leq \left( \sum_{n=1}^\infty a_n^2 \right) \left( \sum_{n=1}^\infty b_n^2 \right). Here:

  • Let an=ana_n = a_n (as given).
  • Choose bn=1nb_n = \frac{1}{n}.

Thus: (n=1ann)2(n=1an2)(n=11n2).\left( \sum_{n=1}^\infty \frac{a_n}{n} \right)^2 \leq \left( \sum_{n=1}^\infty a_n^2 \right) \left( \sum_{n=1}^\infty \frac{1}{n^2} \right).


Justification:

  1. The series n=1an2\sum_{n=1}^\infty a_n^2 converges (given).
  2. The series n=11n2\sum_{n=1}^\infty \frac{1}{n^2} converges, as it is a p-series with p=2>1p = 2 > 1.

Since the right-hand side is finite, it follows that: n=1ann\sum_{n=1}^\infty \frac{a_n}{n} is finite, i.e., the series converges.


Final Answer:

The series n=1ann\sum_{n=1}^\infty \frac{a_n}{n} is convergent.
Correct option: (a) convergent.


Do you need further clarification on the steps? Let me know if you'd like more details.

Related Questions:

  1. What is the Cauchy-Schwarz inequality and how is it applied in series problems?
  2. How does a p-series test determine whether a series converges or diverges?
  3. Why does an2\sum a_n^2 converging impose restrictions on ana_n's behavior?
  4. Can ann\sum \frac{a_n}{n} still converge if an2a_n^2 diverges? Why or why not?
  5. How can other inequalities (like Hölder's inequality) be used to determine series convergence?

Tip:

When analyzing convergence of series involving powers or fractions, always consider comparison tests, inequalities, and behavior of related p-series.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Cauchy-Schwarz Inequality
Comparison Test
p-Series

Formulas

Cauchy-Schwarz Inequality: (∑ aₙbₙ)² ≤ (∑ aₙ²)(∑ bₙ²)
p-Series Convergence: ∑ (1/n^p) converges if p > 1

Theorems

Cauchy-Schwarz Inequality
p-Series Test

Suitable Grade Level

Undergraduate Math / Advanced High School