Math Problem Statement
g(x)=sec x [0,2π]
Solution
To find the behavior of the function over the interval , let's break it down:
1. Definition of :
The secant function is defined as: This function is undefined when , because division by zero is undefined.
2. Points where is undefined:
The cosine function equals zero at the following points in the interval : Thus, has vertical asymptotes at and .
3. Behavior of between critical points:
- In the interval , , so .
- In the interval , , so .
- In the interval , , so .
- In the interval , , so .
4. Range of :
Since is the reciprocal of , and , the range of is: This means that never takes values between -1 and 1.
5. Graphical behavior:
- There are vertical asymptotes at and .
- The graph alternates between positive and negative values, going to near , , and , and near and .
Would you like further details on any of these points or a specific graph of the function?
Here are 5 related questions to expand on this:
- What is the domain of the secant function?
- How do you find vertical asymptotes for trigonometric functions?
- What are the key properties of and how do they compare with ?
- How can you determine intervals of increase and decrease for ?
- How do other reciprocal trigonometric functions behave over ?
Tip: The secant function tends to infinity near the points where approaches zero. Understanding this behavior helps in identifying its vertical asymptotes.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Trigonometry
Secant Function
Behavior of Trigonometric Functions
Formulas
g(x) = sec(x) = 1 / cos(x)
Theorems
Reciprocal Trigonometric Function
Vertical Asymptotes in Trigonometric Functions
Suitable Grade Level
Grades 10-12