In a rhombus, opposite angles are equal, and adjacent angles are supplementary (i.e., they add up to 180º). Here's the step-by-step reasoning:

1. Given information: $m \angle CAB = 35^\circ$.
2. Opposite angles: In a rhombus, opposite angles are equal, so $m \angle DAB = m \angle CAB = 35^\circ$.
3. Adjacent angles: Adjacent angles in a rhombus are supplementary, so: $m \angle DAB + m \angle CDA = 180^\circ$ Substituting $m \angle DAB = 35^\circ$: $35^\circ + m \angle CDA = 180^\circ$ Solving for $m \angle CDA$: $m \angle CDA = 180^\circ - 35^\circ = 145^\circ$

Thus, $m \angle CDA = 145^\circ$.

Would you like a further explanation or have any questions? Here are a few related questions you might find interesting:

1. How do you calculate the angles in a parallelogram?
2. What are the properties of the diagonals of a rhombus?
3. How can you prove that opposite angles of a rhombus are equal?
4. How do you calculate the area of a rhombus given its side length and one of the angles?
5. What is the relationship between the diagonals and angles in a rhombus?

Tip: Always remember that the sum of the interior angles of any quadrilateral is 360º, which helps in angle-related problems!