Math Problem Statement
Solution
The given problem involves using the Remainder Estimation Theorem to find an interval containing over which the function can be approximated by the polynomial with a three-decimal-place accuracy.
Let's go step by step:
Step 1: Taylor Series Approximation
The Taylor series for around is: The polynomial is the Taylor polynomial of degree 3 for .
Step 2: Remainder Estimation Theorem
The remainder after the third term in the Taylor series for is given by: For , we are using the third-degree polynomial, so the remainder is the next term in the Taylor series: We need to find the maximum value of such that this remainder is less than or equal to (since three decimal places means the error must be less than ).
Step 3: Solve for
We want: Solving for : Now, I'll compute the fifth root of .The value of such that the remainder is less than or equal to is approximately .
Thus, the interval over which can be approximated by with three-decimal accuracy is .
Would you like further details or have any other questions?
Here are 5 related questions:
- How does the Remainder Estimation Theorem apply to higher-degree polynomials?
- What happens to the interval if we include more terms in the Taylor expansion?
- How does the error bound change if we require four decimal places of accuracy?
- What are other common functions approximated using Taylor series?
- How do we handle the error in approximations for functions that are not smooth?
Tip: When approximating functions using Taylor series, increasing the degree of the polynomial generally increases the accuracy over a larger interval.
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Math Problem Analysis
Mathematical Concepts
Taylor Series
Remainder Estimation Theorem
Polynomial Approximation
Formulas
f(x) = sin(x)
p(x) = x − x^3/3!
R_3(x) = x^5/120
Theorems
Remainder Estimation Theorem
Suitable Grade Level
College-level Calculus
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