Math Problem Statement
Two trains are coming from opposite directions with speeds of 75 km/hr and 100 km/hr on two parallel tracks. At some moment the distance between them is 100 km. After T hours, distance between them is again 100 km. T is equal to
Solution
The two trains are approaching each other on parallel tracks with speeds of 75 km/h and 100 km/h, and the initial distance between them is 100 km. We need to find the time when the distance between them becomes 100 km again after passing each other.
Step 1: Combined Speed of Trains
When two objects move towards each other, their relative speed is the sum of their individual speeds. Therefore, the relative speed of the two trains is:
Step 2: Total Distance Traveled
After passing each other, the total distance traveled by both trains when the distance between them becomes 100 km again is:
- Initially, the distance between them is 100 km.
- After crossing, the trains must travel enough distance so that their separation becomes 100 km again.
This means the total distance traveled by the two trains is:
Step 3: Time Calculation
Since the two trains are moving towards each other with a relative speed of 175 km/h, the time required to cover 200 km at this speed is:
Final Answer:
The time is hours, or approximately 1.14 hours.
Would you like more details or have any questions?
Here are some related questions for you to consider:
- How would the solution change if both trains had the same speed?
- What if the initial distance between the trains was different?
- How would the problem differ if one train was stationary?
- Can you calculate how far each train has traveled by the time they meet?
- How would the solution change if the two trains were traveling in the same direction?
Tip: When objects move towards each other, their relative speed is the sum of their individual speeds!
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Math Problem Analysis
Mathematical Concepts
Relative Speed
Distance
Time
Formulas
Relative speed = speed of train 1 + speed of train 2
Time (T) = Total distance / Relative speed
Theorems
Basic Kinematic Equation (Distance = Speed × Time)
Suitable Grade Level
Grades 9-12
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