Let's solve the problem from the image you've uploaded.

We are given:

• Point $U$ at $(6, 3)$.
• Point $U$ is reflected over the x-axis to create $U'$.
• Then, $U'$ is reflected over the y-axis to create $U''$.

Step 1: Reflecting over the x-axis

When a point $(x, y)$ is reflected over the x-axis, the y-coordinate changes sign. Thus, reflecting point $U(6, 3)$ over the x-axis gives: $U' = (6, -3)$

Step 2: Reflecting over the y-axis

When a point $(x, y)$ is reflected over the y-axis, the x-coordinate changes sign. Reflecting point $U'(6, -3)$ over the y-axis gives: $U'' = (-6, -3)$

Final Answer:

The coordinates of $U''$ are $(-6, -3)$.

Would you like further details or have any questions? Here are five related questions that might help expand on this concept:

1. What happens when a point is reflected over both axes simultaneously?
2. How do you reflect a point over any arbitrary line (like $y = x$)?
3. What would the coordinates be if $U$ were reflected over the line $y = x$?
4. Can you generalize a formula for reflecting any point over the origin?
5. What is the effect of multiple reflections on the position of a point?

Tip: Always remember that reflecting over the x-axis only affects the y-coordinate, and reflecting over the y-axis only affects the x-coordinate!