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We are given:
- Point \( U \) at \( (6, 3) \).
- Point \( U \) is reflected over the **x-axis** to create \( U' \).
- Then, \( U' \) is reflected over the **y-axis** to create \( U'' \).

### Step 1: Reflecting over the x-axis
When a point \( (x, y) \) is reflected over the x-axis, the y-coordinate changes sign. Thus, reflecting point \( U(6, 3) \) over the x-axis gives:
\[
U' = (6, -3)
\]

### Step 2: Reflecting over the y-axis
When a point \( (x, y) \) is reflected over the y-axis, the x-coordinate changes sign. Reflecting point \( U'(6, -3) \) over the y-axis gives:
\[
U'' = (-6, -3)
\]

### Final Answer:
The coordinates of \( U'' \) are \( (-6, -3) \).

Would you like further details or have any questions? Here are five related questions that might help expand on this concept:

1. What happens when a point is reflected over both axes simultaneously?
2. How do you reflect a point over any arbitrary line (like \( y = x \))?
3. What would the coordinates be if \( U \) were reflected over the line \( y = x \)?
4. Can you generalize a formula for reflecting any point over the origin?
5. What is the effect of multiple reflections on the position of a point?

**Tip:** Always remember that reflecting over the x-axis only affects the y-coordinate, and reflecting over the y-axis only affects the x-coordinate!

Point U is located at (6, 3) on the coordinate plane. Point U is reflected over the x-axis to create point U'. Point U' is then reflected over the y-axis to create point U''. What ordered pair describes the location of U''?

Learn how to find the coordinates of a point reflected over the x-axis and y-axis. In this problem, point U at (6, 3) is reflected over both axes to find the location of U''. Perfect for students learning about reflections and transformations in Grades 7-9.

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