Math Problem Statement

reference angle for -8pi/9

Solution

To find the reference angle for 8π9-\frac{8\pi}{9}, follow these steps:

Step 1: Determine the angle's equivalent in the positive direction

Since the angle is negative, we first convert it to a positive equivalent by adding 2π2\pi (a full circle in radians) until the angle falls within the standard 0θ<2π0 \leq \theta < 2\pi range:

8π9+2π=8π9+18π9=10π9-\frac{8\pi}{9} + 2\pi = -\frac{8\pi}{9} + \frac{18\pi}{9} = \frac{10\pi}{9}

Thus, 10π9\frac{10\pi}{9} is the coterminal positive angle.

Step 2: Identify the quadrant of the angle

Since 10π9\frac{10\pi}{9} is between π\pi and 2π2\pi (since π=9π9\pi = \frac{9\pi}{9} and 2π=18π92\pi = \frac{18\pi}{9}), the angle is located in the third quadrant.

Step 3: Find the reference angle

The reference angle is the acute angle formed with the x-axis. In the third quadrant, the reference angle is calculated by subtracting π\pi from the given angle:

Reference Angle=10π9π=10π99π9=π9\text{Reference Angle} = \frac{10\pi}{9} - \pi = \frac{10\pi}{9} - \frac{9\pi}{9} = \frac{\pi}{9}

Thus, the reference angle for 8π9-\frac{8\pi}{9} is π9\frac{\pi}{9}.


Would you like more details on reference angles or have any questions?

Here are 5 related questions to explore:

  1. What is the reference angle for 7π6\frac{7\pi}{6}?
  2. How do you convert an angle from degrees to radians?
  3. What is a coterminal angle and how is it calculated?
  4. How do you determine in which quadrant an angle lies?
  5. How do reference angles help in evaluating trigonometric functions?

Tip: When working with radians, remember that 2π2\pi represents a full circle, so adjusting angles by adding or subtracting 2π2\pi can simplify negative or large angles.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Reference Angles
Radians
Quadrants

Formulas

Coterminal Angle Formula: θ + 2πn (for positive angles)
Reference Angle Formula: |θ - π| for third quadrant angles

Theorems

Reference Angle Theorem
Coterminal Angle Theorem

Suitable Grade Level

Grades 10-12