Math Problem Statement

Pn=Pn-1+115, P0=80

Solution

The problem you've provided represents a recursive sequence defined as:

Pn=Pn1+115withP0=80P_n = P_{n-1} + 115 \quad \text{with} \quad P_0 = 80

To find the general term PnP_n, we can observe the pattern. Here's a step-by-step breakdown:

  1. P0=80P_0 = 80
  2. P1=P0+115=80+115=195P_1 = P_0 + 115 = 80 + 115 = 195
  3. P2=P1+115=195+115=310P_2 = P_1 + 115 = 195 + 115 = 310
  4. P3=P2+115=310+115=425P_3 = P_2 + 115 = 310 + 115 = 425
  5. And so on.

General Formula:

We can deduce a general form for PnP_n from the recursive formula. The recurrence relation is arithmetic, with a common difference of 115. For an arithmetic sequence, the general term is given by:

Pn=P0+ndP_n = P_0 + n \cdot d

Where:

  • P0=80P_0 = 80 (initial value),
  • d=115d = 115 (common difference),
  • nn is the term number.

Thus, the general term for PnP_n is:

Pn=80+115nP_n = 80 + 115n

Example:

To calculate P4P_4, we use the formula:

P4=80+115×4=80+460=540P_4 = 80 + 115 \times 4 = 80 + 460 = 540

Would you like further details, or do you have any questions?

Here are 5 related questions to deepen understanding:

  1. How would the general formula change if the initial value P0P_0 were different?
  2. What if the common difference were negative?
  3. How would you solve for nn if a specific PnP_n value is given?
  4. Can this sequence be related to any real-world scenarios like savings or investments?
  5. How would a geometric progression differ from this arithmetic sequence?

Tip: Recognizing a recursive pattern can often help simplify and find the general term of a sequence.

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Math Problem Analysis

Mathematical Concepts

Algebra
Sequences and Series
Arithmetic Progressions

Formulas

Pn = P0 + n * d (General formula for arithmetic progression)

Theorems

Arithmetic Progression Theorem

Suitable Grade Level

Grades 8-10