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The question is asking for the rationalized form of the following expression:

\[
\frac{36}{\sqrt{11} - \sqrt{2}}
\]

To rationalize this expression, we multiply both the numerator and denominator by the conjugate of the denominator, which is \(\sqrt{11} + \sqrt{2}\). This will help eliminate the square roots from the denominator.

### Step 1: Multiply by the conjugate
\[
\frac{36}{\sqrt{11} - \sqrt{2}} \times \frac{\sqrt{11} + \sqrt{2}}{\sqrt{11} + \sqrt{2}} = \frac{36(\sqrt{11} + \sqrt{2})}{(\sqrt{11} - \sqrt{2})(\sqrt{11} + \sqrt{2})}
\]

### Step 2: Simplify the denominator
The denominator is a difference of squares, which simplifies as follows:
\[
(\sqrt{11})^2 - (\sqrt{2})^2 = 11 - 2 = 9
\]

Thus, the expression becomes:
\[
\frac{36(\sqrt{11} + \sqrt{2})}{9}
\]

### Step 3: Simplify the fraction
\[
\frac{36}{9} = 4
\]

Therefore, the expression simplifies to:
\[
4(\sqrt{11} + \sqrt{2})
\]

### Final Answer:
The correct answer is **A: \( 4(\sqrt{11} + \sqrt{2}) \)**.

---

Would you like more details or have any questions? 

Here are some related questions you could explore:
1. How do you rationalize more complex expressions with three terms?
2. What is the importance of using the conjugate when rationalizing?
3. How does the difference of squares help in rationalizing denominators?
4. Can rationalization be applied to expressions with cube roots?
5. What are some real-world applications of rationalizing denominators?

**Tip:** Always check if the denominator is a difference of squares when rationalizing expressions, as it can simplify the process significantly.

Bentuk rasional dari akar \(\frac{36}{\sqrt{11} - \sqrt{2}}\) adalah ...

Explore how to rationalize the denominator of the expression \(\frac{36}{\sqrt{11} - \sqrt{2}}\) by using the conjugate method. This solution involves key algebraic concepts such as the difference of squares and is suitable for students in Grades 10-12.

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