Math Problem Statement

The curved surface area of a right circular cone is half of another right circular cone. If the ratio of their slant heights is 2:1 and that of their volumes is 3:1, find ratio of their: (a) radii (b) heights

Solution

We are given two right circular cones with specific relationships:

  1. The curved surface area (CSA) of the first cone is half of that of the second cone.
  2. The ratio of their slant heights is 2:1.
  3. The ratio of their volumes is 3:1.

We are asked to find the ratio of their radii and heights.

Key formulas:

  • Curved Surface Area (CSA) of a cone:
    CSA=πrl\text{CSA} = \pi r l
    where rr is the radius and ll is the slant height.

  • Volume of a cone:
    V=13πr2hV = \frac{1}{3} \pi r^2 h
    where rr is the radius and hh is the height.

Let’s denote:

  • r1r_1 and r2r_2 as the radii of the two cones,
  • l1l_1 and l2l_2 as the slant heights of the two cones,
  • h1h_1 and h2h_2 as the heights of the two cones.

Step 1: Using the ratio of the curved surface areas

We know: CSA of cone 1=12×CSA of cone 2\text{CSA of cone 1} = \frac{1}{2} \times \text{CSA of cone 2} Thus: πr1l1=12×πr2l2\pi r_1 l_1 = \frac{1}{2} \times \pi r_2 l_2 Simplifying: r1l1=12r2l2r_1 l_1 = \frac{1}{2} r_2 l_2 We are also given that the ratio of slant heights is l1:l2=2:1l_1 : l_2 = 2:1, i.e., l1=2l2l_1 = 2l_2.

Substituting l1=2l2l_1 = 2l_2 into the equation: r1×2l2=12r2×l2r_1 \times 2l_2 = \frac{1}{2} r_2 \times l_2 Canceling l2l_2 from both sides: r1×2=12r2r_1 \times 2 = \frac{1}{2} r_2 Thus: r1=r24r_1 = \frac{r_2}{4} So, the ratio of the radii is: r1:r2=1:4r_1 : r_2 = 1:4

Step 2: Using the ratio of the volumes

We know: V1V2=31\frac{V_1}{V_2} = \frac{3}{1} That is: 13πr12h113πr22h2=31\frac{\frac{1}{3} \pi r_1^2 h_1}{\frac{1}{3} \pi r_2^2 h_2} = \frac{3}{1} Simplifying: r12h1r22h2=3\frac{r_1^2 h_1}{r_2^2 h_2} = 3 Substituting r1=r24r_1 = \frac{r_2}{4}: (r24)2h1r22h2=3\frac{\left(\frac{r_2}{4}\right)^2 h_1}{r_2^2 h_2} = 3 Simplifying: r2216h1r22h2=3\frac{\frac{r_2^2}{16} h_1}{r_2^2 h_2} = 3 Canceling r22r_2^2 from both sides: h116h2=3\frac{h_1}{16 h_2} = 3 Thus: h1=48h2h_1 = 48 h_2 So, the ratio of the heights is: h1:h2=48:1h_1 : h_2 = 48:1

Final Answer:

(a) The ratio of their radii is 1:41:4.
(b) The ratio of their heights is 48:148:1.

Would you like further details on these calculations or additional questions?

Here are 5 related questions to expand your understanding:

  1. How does changing the radius affect the curved surface area of a cone?
  2. If the height of a cone doubles, how is its volume affected?
  3. How would the ratio of slant heights affect the volume ratio of two cones?
  4. Can you derive a relationship between the slant height and the height of a cone?
  5. How is the lateral area of a cone related to its radius and height?

Tip: When comparing geometric shapes, understanding the relation between different dimensions like height, radius, and slant height can simplify your approach to problem-solving.

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Math Problem Analysis

Mathematical Concepts

Geometry
Cone
Surface Area
Volume Ratios
Proportions

Formulas

Curved Surface Area of a Cone = π * r * l
Volume of a Cone = (1/3) * π * r^2 * h

Theorems

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Suitable Grade Level

Grades 9-11