Math Problem Statement
Solution
The problem asks for the rate at which revenue is changing with respect to time when the price of the widgets is increasing by $4 per month and the current price is $150.
We are given the number of items sold in terms of the price by the equation:
Revenue is the product of the number of items sold and the price per item:
To find the rate at which revenue is changing when , we need to calculate , where (the price is increasing by $4 per month).
Steps:
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First, differentiate the revenue function with respect to using the product rule:
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Then use the chain rule to find .
Let me calculate the derivative and the final rate.The derivative of the revenue function with respect to price, evaluated at , is:
The rate of change of revenue with respect to time , considering that , is:
Let me now compute the numerical value of this.The rate at which revenue is changing when the price is $150 and increasing by $4 per month is approximately dollars per month.
Would you like further clarification or more details on any step? Here are five related questions to expand on this:
- How does the product rule apply in this scenario for differentiating the revenue function?
- What effect does increasing price have on the number of items sold?
- How would the rate of change in revenue differ if the price were increasing at a different rate?
- What would happen if we considered the maximum price before revenue starts to decrease?
- How can the second derivative help in understanding the behavior of revenue with respect to price?
Tip: Always check whether a function is increasing or decreasing by examining the sign of its first derivative over the domain of interest.
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Math Problem Analysis
Mathematical Concepts
Calculus
Rate of Change
Product Rule
Formulas
x = 70000 / sqrt(2p + 1)
R = x * p
dR/dt = dR/dp * dp/dt
Theorems
Product Rule
Chain Rule
Suitable Grade Level
Grades 11-12 or College Calculus
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