You have uploaded an image with three functions for which you are likely asked to determine the range. I'll guide you through the process for each function step by step.

The functions are:

1. $f(x) = \frac{5x - 1}{x - 4}$
2. $f(x) = \frac{2x + 1}{4x + 8}$
3. $f(x) = \frac{3x}{3x - 7}$

Method to Find the Range:

For rational functions like these, we typically examine the behavior as $x$ approaches critical values like vertical asymptotes or zeros in the denominator. Here's the procedure for each function:

1. $f(x) = \frac{5x - 1}{x - 4}$

• The function has a vertical asymptote where the denominator equals zero, i.e., $x = 4$.
• To find the range, solve $y = \frac{5x - 1}{x - 4}$ for $x$: $y(x - 4) = 5x - 1$ $yx - 4y = 5x - 1$ Rearrange the terms and solve for $x$ in terms of $y$. Afterward, check if there are any restrictions on $y$ based on the asymptotic behavior.

2. $f(x) = \frac{2x + 1}{4x + 8}$

• First, simplify the denominator: $f(x) = \frac{2x + 1}{4(x + 2)}$
• The vertical asymptote is where $x = -2$.
• Similarly, solve $y = \frac{2x + 1}{4x + 8}$ for $x$ in terms of $y$ to find the range.

3. $f(x) = \frac{3x}{3x - 7}$

• Here, there is a vertical asymptote at $x = \frac{7}{3}$.
• To determine the range, solve $y = \frac{3x}{3x - 7}$ for $x$, and check for restrictions on $y$.

Let me solve each of these functions' ranges. Shall I proceed with the algebra?