Math Problem Statement

If x,y,z are positive and x+y+z =6 what is the range of value of (x/y)+ (y/z)+z(/x)

Solution

Given that xx, yy, and zz are positive numbers and x+y+z=6x + y + z = 6, we are asked to find the range of the expression:

xy+yz+zx\frac{x}{y} + \frac{y}{z} + \frac{z}{x}

To approach this, we can apply the Arithmetic Mean-Geometric Mean (AM-GM) inequality, which states that for any positive real numbers aa, bb, and cc:

ab+bc+ca3\frac{a}{b} + \frac{b}{c} + \frac{c}{a} \geq 3

Equality holds in the AM-GM inequality if and only if xy=yz=zx\frac{x}{y} = \frac{y}{z} = \frac{z}{x}, implying x=y=zx = y = z.

Step-by-Step Solution:

  1. Apply AM-GM Inequality: Using AM-GM inequality directly on our expression:

    xy+yz+zx3\frac{x}{y} + \frac{y}{z} + \frac{z}{x} \geq 3

    This gives us a lower bound of 3.

  2. Evaluate When x=y=zx = y = z: If x=y=zx = y = z, then from x+y+z=6x + y + z = 6 we get 3x=63x = 6 or x=2x = 2. Thus, x=y=z=2x = y = z = 2.

    Substituting x=y=z=2x = y = z = 2 into the expression:

    xy+yz+zx=22+22+22=1+1+1=3\frac{x}{y} + \frac{y}{z} + \frac{z}{x} = \frac{2}{2} + \frac{2}{2} + \frac{2}{2} = 1 + 1 + 1 = 3

    So, the minimum value of the expression is 3.

  3. Explore the Upper Bound: For the upper bound, we consider that as xx, yy, and zz vary under the constraint x+y+z=6x + y + z = 6, the expression xy+yz+zx\frac{x}{y} + \frac{y}{z} + \frac{z}{x} can increase significantly if there is a large disparity among xx, yy, and zz.

    However, without specific values, the upper bound is challenging to determine precisely. In many cases, with positive numbers and constraints like x+y+z=6x + y + z = 6, this expression does not have a finite upper bound as the terms can diverge if one variable approaches zero. Thus, the expression can grow arbitrarily large.

Conclusion

The range of the expression xy+yz+zx\frac{x}{y} + \frac{y}{z} + \frac{z}{x} is:

[3,)[3, \infty)

Would you like further details on any specific steps?


Related Questions

  1. How would the range change if xx, yy, and zz were bounded differently?
  2. What happens if we add additional constraints to xx, yy, and zz?
  3. How can the AM-GM inequality be applied to other expressions with similar forms?
  4. How would we approach this if xx, yy, and zz were restricted to integer values?
  5. Can we use calculus to explore the range for a minimum or maximum value?

Tip: AM-GM inequality is a powerful tool for establishing bounds, particularly with symmetric expressions in positive variables.

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Math Problem Analysis

Mathematical Concepts

Algebra
Inequalities
Arithmetic Mean-Geometric Mean (AM-GM) Inequality

Formulas

AM-GM Inequality: a/b + b/c + c/a >= 3

Theorems

Arithmetic Mean-Geometric Mean Inequality

Suitable Grade Level

Grades 11-12