Math Problem Statement

A cuboid has a square base of length 3 cm. The total surface area of the cuboid is not greater than 210 cm² and the volume of the cuboid is not less than 90 cm³. Given that DE is x cm, find the range of values for x. An ant crawls from point B to point E on the surface of the cuboid via any point Y on CH, taking the shortest path. (i) Is it possible for ∠CBY to be equal to 50°? Explain your answer. (ii) Chloe claims that the length of the path will not be greater than 18 cm. Do you agree? Explain your answer.

Solution

Let's analyze the problem step by step based on the given conditions.

Given:

  1. A cuboid with a square base of length 3 cm3 \text{ cm}, meaning the base dimensions are 3 cm×3 cm3 \text{ cm} \times 3 \text{ cm}.
  2. The height of the cuboid is x cmx \text{ cm}.
  3. Total surface area of the cuboid is not greater than 210 cm2210 \text{ cm}^2.
  4. Volume of the cuboid is not less than 90 cm390 \text{ cm}^3.

Part (a): Finding the range of values for xx.

Step 1: Surface Area Constraint

The surface area of a cuboid is given by: Surface Area=2(lw+lh+wh)\text{Surface Area} = 2(lw + lh + wh) where ll, ww, and hh are the length, width, and height of the cuboid, respectively. In this problem, l=w=3 cml = w = 3 \text{ cm}, and h=x cmh = x \text{ cm}.

Substituting these values: Surface Area=2(33+3x+3x)=2(9+6x)=18+12x\text{Surface Area} = 2(3 \cdot 3 + 3 \cdot x + 3 \cdot x) = 2(9 + 6x) = 18 + 12x The surface area must be less than or equal to 210 cm2210 \text{ cm}^2: 18+12x21018 + 12x \leq 210 Solving for xx: 12x19212x \leq 192 x16x \leq 16

Step 2: Volume Constraint

The volume of a cuboid is given by: Volume=lwh=33x=9x\text{Volume} = l \cdot w \cdot h = 3 \cdot 3 \cdot x = 9x The volume must be at least 90 cm390 \text{ cm}^3: 9x909x \geq 90 Solving for xx: x10x \geq 10

Conclusion for Part (a)

Combining the two constraints, the range of values for xx is: 10x1610 \leq x \leq 16

Part (b)(i): Is it possible for CBY\angle CBY to be equal to 5050^\circ?

To determine if CBY\angle CBY can be 5050^\circ, we would need to find the shortest path for the ant from BB to EE along the surface. The path typically involves unfolding the cuboid into a plane and finding the straight-line distance on this flattened representation. Calculating the exact angle would involve trigonometric analysis based on the path's geometry, which would depend on the position of YY.

Part (b)(ii): Is the path length less than or equal to 18 cm?

To find the shortest path from BB to EE, consider unfolding the cuboid into a rectangle. The rectangle formed by unfolding BCDEHGBCDEHG would have dimensions 3 cm×(3+x)3 \text{ cm} \times (3 + x). The shortest path can be found using the Pythagorean theorem: Shortest Path=(3+x)2+32\text{Shortest Path} = \sqrt{(3 + x)^2 + 3^2} Substitute 10x1610 \leq x \leq 16 and calculate if the path length satisfies the condition.

Would you like more details on any of these parts?

Additional Questions:

  1. What happens to the range of xx if the surface area constraint changes?
  2. How would the shortest path change if the base dimensions were different?
  3. What trigonometric functions would be needed to solve for CBY\angle CBY?
  4. How does increasing the cuboid's height affect the shortest path?
  5. Can you find another method to calculate the shortest path besides unfolding?

Tip:

For complex geometric problems, visualizing the 3D object as a 2D net can simplify the calculations significantly.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Surface Area
Volume
Pythagorean Theorem
Angles

Formulas

Surface Area of cuboid = 2(lw + lh + wh)
Volume of cuboid = l × w × h
Shortest Path in 2D (using Pythagoras): √(a² + b²)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-11