Math Problem Statement

Use graphing technology to find the range of the function f(x) = √(x + 5) - 3.

Solution

The function given in the image is:

f(x)=x+53f(x) = \sqrt{x + 5} - 3

To find the range of this function using graphing technology, you can analyze the behavior of the function step-by-step.

Steps to find the range:

  1. Domain: The square root function x+5\sqrt{x + 5} requires that the expression inside the square root must be non-negative. This means: x+50x5x + 5 \geq 0 \quad \Rightarrow \quad x \geq -5 Therefore, the domain of the function is x5x \geq -5.

  2. Minimum Value of the Function:

    • At x=5x = -5, the function simplifies to: f(5)=5+53=03=3f(-5) = \sqrt{-5 + 5} - 3 = \sqrt{0} - 3 = -3 So, the minimum value of f(x)f(x) is 3-3.
  3. Behavior as xx \to \infty:

    • As xx increases, x+5\sqrt{x + 5} increases without bound, so the function f(x)=x+53f(x) = \sqrt{x + 5} - 3 also increases without bound.
  4. Conclusion:

    • The range of the function is all values starting from 3-3 to infinity. In interval notation, the range is: Range of f(x):[3,)\text{Range of } f(x): [-3, \infty)

Would you like further details on graphing or clarification on this process?

Related questions:

  1. How do you find the domain of functions involving square roots?
  2. What is the impact of a horizontal shift on the range of a function?
  3. How does adding or subtracting constants outside a square root affect the graph of a function?
  4. How can you confirm the range of a function using graphing tools like Desmos?
  5. Can the range of this function be influenced by any other transformations?

Tip: When dealing with square root functions, always first check the domain, as it restricts the range directly.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions
Square Root Function

Formulas

f(x) = √(x + 5) - 3

Theorems

Domain and Range Theorems for Functions

Suitable Grade Level

Grades 9-12