It looks like the question is incomplete or possibly misphrased. You might be asking about finding the radius of the circle inscribed in a right-angled isosceles triangle with a given hypotenuse.

For a right-angled isosceles triangle, where the two legs are equal and the hypotenuse is given, the radius $r$ of the inscribed circle can be calculated using the formula:

$r = \frac{a(\sqrt{2}-1)}{2}$ where $a$ is the length of each leg of the triangle.

In your case, you provided the hypotenuse as $62$, but there seems to be confusion about "162." I'll assume the hypotenuse is $62$.

For a right-angled isosceles triangle, the relationship between the hypotenuse $c$ and the legs $a$ is given by:

$c = a\sqrt{2}$

So, we can find the length of the legs $a$ by solving for $a$:

$a = \frac{c}{\sqrt{2}} = \frac{62}{\sqrt{2}} = \frac{62 \times \sqrt{2}}{2} = 31\sqrt{2}$

Now, using this in the formula for the inscribed circle's radius:

$r = \frac{31\sqrt{2}(\sqrt{2}-1)}{2}$

Would you like further clarifications or help solving this step-by-step?

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Here are some related questions you might consider:

1. What is the relationship between the hypotenuse and legs in an isosceles right triangle?
2. How do you find the area of a right-angled isosceles triangle?
3. How can you derive the formula for the radius of an inscribed circle in different triangles?
4. What is the formula for the circumradius of a right triangle?
5. Can you find the perimeter of a right-angled isosceles triangle?

Tip: In an isosceles right triangle, the hypotenuse is always $\sqrt{2}$ times longer than each of the legs.