Math Problem Statement
If alpha and beta are the zeroes of the quadratic polynomial, find a quadratic polynomial whose zeroes are 2alpha/beta and 2beta/alpha
Solution
Let the quadratic polynomial be represented as:
Given that and are the zeroes of this polynomial, we know the following relationships from Vieta's formulas:
- The sum of the roots
- The product of the roots
We are asked to find a new quadratic polynomial whose zeroes are and .
To do this, we need to compute:
-
The sum of the new zeroes:
Using the identity , we can express the sum as: Now, recall that: Substitute and into the equation: Thus, the sum of the new roots becomes: -
The product of the new zeroes:
Thus, the new quadratic polynomial has the form:
Substituting the values for the sum and product:
This is the required quadratic polynomial.
Would you like further details or have any questions on the steps?
Here are five related questions you might find helpful:
- What are Vieta's formulas and how do they relate to the zeroes of a polynomial?
- How do you simplify algebraic expressions involving fractions like ?
- Can you derive the relationship between the sum of the squares of the roots and the sum and product of the roots in a quadratic polynomial?
- How can you verify that the quadratic polynomial you derived has the correct zeroes?
- What would happen to the polynomial if the coefficients , , and were given specific values?
Tip: To simplify problems involving fractions with variables, always look for common denominators or factorization strategies!
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Math Problem Analysis
Mathematical Concepts
Algebra
Quadratic Equations
Vieta's Formulas
Roots of Polynomials
Formulas
Vieta's formulas: Sum of roots = -b/a, Product of roots = c/a
Sum of new roots = 2 * (alpha/beta + beta/alpha)
alpha^2 + beta^2 = (alpha + beta)^2 - 2*alpha*beta
Theorems
Vieta's Formulas
Sum and product of roots of quadratic equations
Suitable Grade Level
Grades 10-12
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