Math Problem Statement

Let f(x) = 8 + x + x^2 and h ≠ 0. Solve various properties of the function including finding values, differences, and analyzing equality relations.

Solution

Let's analyze the given problem step by step.

We are given the function: f(x)=8+x+x2f(x) = 8 + x + x^2 and h0h \neq 0.

(a) Does f(7+1)=f(7)+f(1)f(7 + 1) = f(7) + f(1)?

We need to evaluate both sides.

  • f(7+1)=f(8)f(7 + 1) = f(8)

    • f(8)=8+8+82=8+8+64=80f(8) = 8 + 8 + 8^2 = 8 + 8 + 64 = 80
  • Now, calculate f(7)+f(1)f(7) + f(1):

    • f(7)=8+7+72=8+7+49=64f(7) = 8 + 7 + 7^2 = 8 + 7 + 49 = 64
    • f(1)=8+1+12=8+1+1=10f(1) = 8 + 1 + 1^2 = 8 + 1 + 1 = 10
    • So, f(7)+f(1)=64+10=74f(7) + f(1) = 64 + 10 = 74

Clearly, f(8)f(7)+f(1)f(8) \neq f(7) + f(1), so the answer is No.


(b) Find f(x+h)f(x + h).

We need to substitute x+hx + h into the function f(x)=8+x+x2f(x) = 8 + x + x^2: f(x+h)=8+(x+h)+(x+h)2f(x + h) = 8 + (x + h) + (x + h)^2 Expanding the expression: f(x+h)=8+x+h+(x2+2xh+h2)f(x + h) = 8 + x + h + (x^2 + 2xh + h^2) Simplifying: f(x+h)=8+x+h+x2+2xh+h2f(x + h) = 8 + x + h + x^2 + 2xh + h^2 Thus, f(x+h)=8+x+x2+h+2xh+h2f(x + h) = 8 + x + x^2 + h + 2xh + h^2.


(c) Does f(x+h)=f(x)+f(h)f(x + h) = f(x) + f(h)?

Let's calculate both sides.

  • f(x+h)=8+x+x2+h+2xh+h2f(x + h) = 8 + x + x^2 + h + 2xh + h^2 (from part b).

  • Now, calculate f(x)+f(h)f(x) + f(h):

    • f(x)=8+x+x2f(x) = 8 + x + x^2
    • f(h)=8+h+h2f(h) = 8 + h + h^2
    • So, f(x)+f(h)=(8+x+x2)+(8+h+h2)=16+x+h+x2+h2f(x) + f(h) = (8 + x + x^2) + (8 + h + h^2) = 16 + x + h + x^2 + h^2

Clearly, f(x+h)f(x)+f(h)f(x + h) \neq f(x) + f(h) because the term 2xh2xh is missing on the right-hand side. So, the answer is No.


(d) Does f(x+h)=f(x)+hf(x + h) = f(x) + h?

Let's compare both sides.

  • f(x+h)=8+x+x2+h+2xh+h2f(x + h) = 8 + x + x^2 + h + 2xh + h^2 (from part b).
  • f(x)+h=(8+x+x2)+h=8+x+x2+hf(x) + h = (8 + x + x^2) + h = 8 + x + x^2 + h

Since f(x+h)f(x + h) contains additional terms 2xh2xh and h2h^2, the answer is No.


(e) Find f(x+h)f(x)h\frac{f(x + h) - f(x)}{h} and simplify.

First, let's compute the difference: f(x+h)f(x)=(8+x+x2+h+2xh+h2)(8+x+x2)f(x + h) - f(x) = (8 + x + x^2 + h + 2xh + h^2) - (8 + x + x^2) Simplifying: f(x+h)f(x)=h+2xh+h2f(x + h) - f(x) = h + 2xh + h^2 Now, divide by hh: f(x+h)f(x)h=h+2xh+h2h\frac{f(x + h) - f(x)}{h} = \frac{h + 2xh + h^2}{h} Simplifying further: f(x+h)f(x)h=1+2x+h\frac{f(x + h) - f(x)}{h} = 1 + 2x + h

Thus, the simplified form is 1+2x+h1 + 2x + h.


Do you need further clarifications or details on any step? Here are 5 related questions to explore:

  1. How does the behavior of f(x)f(x) change as h0h \to 0?
  2. What is the derivative of f(x)=8+x+x2f(x) = 8 + x + x^2?
  3. Can f(x)f(x) be factored in any useful way for solving future problems?
  4. How does the quadratic term x2x^2 impact the difference quotient in part (e)?
  5. How would you solve the limit of the difference quotient as h0h \to 0?

Tip: The difference quotient f(x+h)f(x)h\frac{f(x+h) - f(x)}{h} is a crucial step in finding the derivative of a function!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Difference Quotient

Formulas

f(x) = 8 + x + x^2
f(x + h) = 8 + (x + h) + (x + h)^2 = 8 + x + h + x^2 + 2xh + h^2
Difference Quotient: (f(x+h) - f(x)) / h

Theorems

Quadratic Expansion
Simplification of Polynomial Expressions

Suitable Grade Level

Grades 9-11