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It is given that AB=AD=AE, Angle B equals Angle ADC, and that D is a point on CE. Prove that triangles ABC and AEC have two angles and an angle in front of the shortest side which are respectively equal, but the triangles aren't congruent.

To prove that triangles \( \triangle ABC \) and \( \triangle AEC \) have two angles equal and the angle opposite the shortest side equal but are not congruent, we can proceed as follows:

### Given:
- \( AB = AD = AE \)
- \( \angle B = \angle ADC \)
- \( D \) is a point on \( CE \)

### To Prove:
- \( \triangle ABC \) and \( \triangle AEC \) have two angles equal and the angle opposite the shortest side equal.
- \( \triangle ABC \) and \( \triangle AEC \) are not congruent.

### Proof:

1. **Consider triangles \( \triangle ABC \) and \( \triangle AEC \):**

   - Since \( AB = AE \) (given), triangle \( \triangle ABE \) is isosceles.
   - \( \angle ABC = \angle AEC \) because \( AB = AE \) and \( \angle B = \angle E \) (as corresponding angles of isosceles triangle \( \triangle ABE \)).

2. **Angle Equality:**

   - \( \angle BAC \) is common in both triangles \( \triangle ABC \) and \( \triangle AEC \).
   - Given \( \angle B = \angle ADC \) and because \( AB = AD = AE \), it implies that \( \angle ABC = \angle AEC \).

   Therefore, \( \angle BAC = \angle EAC \), \( \angle ABC = \angle AEC \).

3. **Angle in front of the shortest side:**

   - Since \( AB = AD = AE \), the side \( BC \) in \( \triangle ABC \) and \( EC \) in \( \triangle AEC \) are both opposite the angles \( \angle BAC \) and \( \angle EAC \).
   - \( BC \) and \( EC \) are both equal because the angle in front of these sides in both triangles are equal.

4. **Non-Congruence:**

   - Even though the triangles have two angles and the angle opposite the shortest side equal, \( \triangle ABC \) and \( \triangle AEC \) are not congruent because their corresponding sides (other than the equal ones) are not equal. For example, \( AC \) in \( \triangle ABC \) is not necessarily equal to \( AC \) in \( \triangle AEC \).

   - Additionally, since \( D \) is a point on \( CE \), and \( \angle B = \angle ADC \), this further implies that \( \triangle ABC \) and \( \triangle AEC \) might have different lengths of sides, confirming they are not congruent.

### Conclusion:
Thus, the triangles \( \triangle ABC \) and \( \triangle AEC \) have two angles equal and the angle opposite the shortest side equal, but they are not congruent.

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**Related Questions:**
1. What are the criteria for congruence of triangles?
2. How does the Angle-Side-Angle (ASA) criterion work in proving triangle congruence?
3. What is the importance of an isosceles triangle in geometric proofs?
4. How do corresponding angles in similar triangles behave?
5. Can the properties of a quadrilateral be used to determine triangle congruence?

**Tip:** When analyzing triangle properties, always check the equality of corresponding angles and sides to determine congruence or similarity.

Explore the proof that triangles ABC and AEC have two equal angles and an equal angle opposite the shortest side without being congruent. Detailed geometric analysis involving triangle properties and the ASA criterion.

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