Math Problem Statement

Prove that the points whose position vectors 2 ˆ i + 4 ˆ j + 3 ˆ k , 4 ˆ i + ˆ j + 9 ˆ k and 10 ˆ i − ˆ j + 6 ˆ k form a right angled triangle.

Solution

To prove that the points with the position vectors A=2i^+4j^+3k^\mathbf{A} = 2\hat{i} + 4\hat{j} + 3\hat{k}, B=4i^+j^+9k^\mathbf{B} = 4\hat{i} + \hat{j} + 9\hat{k}, and C=10i^j^+6k^\mathbf{C} = 10\hat{i} - \hat{j} + 6\hat{k} form a right-angled triangle, we will first calculate the vectors representing the sides of the triangle, then check if the Pythagorean theorem holds.

Step 1: Find the vectors representing the sides of the triangle.

  • The vector AB\overrightarrow{AB} represents the side between points AA and BB. AB=BA=(4i^+j^+9k^)(2i^+4j^+3k^)=2i^3j^+6k^\overrightarrow{AB} = \mathbf{B} - \mathbf{A} = (4\hat{i} + \hat{j} + 9\hat{k}) - (2\hat{i} + 4\hat{j} + 3\hat{k}) = 2\hat{i} - 3\hat{j} + 6\hat{k}

  • The vector BC\overrightarrow{BC} represents the side between points BB and CC. BC=CB=(10i^j^+6k^)(4i^+j^+9k^)=6i^2j^3k^\overrightarrow{BC} = \mathbf{C} - \mathbf{B} = (10\hat{i} - \hat{j} + 6\hat{k}) - (4\hat{i} + \hat{j} + 9\hat{k}) = 6\hat{i} - 2\hat{j} - 3\hat{k}

  • The vector CA\overrightarrow{CA} represents the side between points CC and AA. CA=AC=(2i^+4j^+3k^)(10i^j^+6k^)=8i^+5j^3k^\overrightarrow{CA} = \mathbf{A} - \mathbf{C} = (2\hat{i} + 4\hat{j} + 3\hat{k}) - (10\hat{i} - \hat{j} + 6\hat{k}) = -8\hat{i} + 5\hat{j} - 3\hat{k}

Step 2: Check if the triangle is right-angled using the dot product.

In a right-angled triangle, the vectors representing two sides meeting at a right angle will have a dot product of 0. We will compute the dot products of the pairs of vectors AB\overrightarrow{AB}, BC\overrightarrow{BC}, and CA\overrightarrow{CA}.

Dot product of AB\overrightarrow{AB} and BC\overrightarrow{BC}:

ABBC=(2i^3j^+6k^)(6i^2j^3k^)\overrightarrow{AB} \cdot \overrightarrow{BC} = (2\hat{i} - 3\hat{j} + 6\hat{k}) \cdot (6\hat{i} - 2\hat{j} - 3\hat{k}) =2×6+(3)×(2)+6×(3)=12+618=0= 2 \times 6 + (-3) \times (-2) + 6 \times (-3) = 12 + 6 - 18 = 0 Since the dot product is 0, the vectors AB\overrightarrow{AB} and BC\overrightarrow{BC} are perpendicular, meaning the angle between them is 90°.

Step 3: Conclusion.

Since the dot product of AB\overrightarrow{AB} and BC\overrightarrow{BC} is 0, the triangle formed by the points AA, BB, and CC is a right-angled triangle with the right angle at point BB.


Would you like further details or have any questions about this solution?

Further Questions:

  1. How do you calculate the length of the sides of a triangle given the position vectors of the vertices?
  2. What are the properties of a right-angled triangle in vector geometry?
  3. How can the cross product be used to check for perpendicular vectors in three-dimensional space?
  4. How do you apply the law of cosines in vector form?
  5. How do you find the area of a right-angled triangle using vectors?

Tip: The dot product is an essential tool for checking orthogonality (perpendicularity) of vectors, which is useful in many geometry problems.

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Math Problem Analysis

Mathematical Concepts

Vector Geometry
Dot Product
Right-Angled Triangle

Formulas

Vector between two points: \( \overrightarrow{AB} = \mathbf{B} - \mathbf{A} \)
Dot product formula: \( \mathbf{A} \cdot \mathbf{B} = A_xB_x + A_yB_y + A_zB_z \)

Theorems

Pythagorean Theorem in vector form

Suitable Grade Level

Grades 11-12