Math Problem Statement

prove that $\vec{U} = \binom{2}{-3}$ is a linear combination of the vectors $\vec{V}_1 = \binom{-0.5}{2}$ and $\vec{V}_2 = \binom{1}{1}$,

Solution

To prove that U=(23)\vec{U} = \begin{pmatrix} 2 \\ -3 \end{pmatrix} is a linear combination of the vectors V1=(0.52)\vec{V}_1 = \begin{pmatrix} -0.5 \\ 2 \end{pmatrix} and V2=(11)\vec{V}_2 = \begin{pmatrix} 1 \\ 1 \end{pmatrix}, we need to find scalars aa and bb such that:

U=aV1+bV2\vec{U} = a \vec{V}_1 + b \vec{V}_2

Substituting the given vectors into this equation, we get:

(23)=a(0.52)+b(11)\begin{pmatrix} 2 \\ -3 \end{pmatrix} = a \begin{pmatrix} -0.5 \\ 2 \end{pmatrix} + b \begin{pmatrix} 1 \\ 1 \end{pmatrix}

This equation can be written as a system of linear equations:

(23)=(0.5a+b2a+b)\begin{pmatrix} 2 \\ -3 \end{pmatrix} = \begin{pmatrix} -0.5a + b \\ 2a + b \end{pmatrix}

This gives us the following system of equations:

0.5a+b=2(1)-0.5a + b = 2 \quad \text{(1)}

2a+b=3(2)2a + b = -3 \quad \text{(2)}

We can solve this system using substitution or elimination. First, let's solve equation (1) for bb:

b=2+0.5ab = 2 + 0.5a

Next, substitute this expression for bb into equation (2):

2a+(2+0.5a)=32a + (2 + 0.5a) = -3

Simplify and solve for aa:

2a+2+0.5a=32a + 2 + 0.5a = -3

2.5a+2=32.5a + 2 = -3

2.5a=52.5a = -5

a=2a = -2

Now, substitute a=2a = -2 back into the expression for bb:

b=2+0.5(2)b = 2 + 0.5(-2)

b=21b = 2 - 1

b=1b = 1

Therefore, the scalars a=2a = -2 and b=1b = 1 satisfy the system of equations. Thus, we can write:

U=2V1+1V2\vec{U} = -2 \vec{V}_1 + 1 \vec{V}_2

So, U=(23)\vec{U} = \begin{pmatrix} 2 \\ -3 \end{pmatrix} is indeed a linear combination of V1=(0.52)\vec{V}_1 = \begin{pmatrix} -0.5 \\ 2 \end{pmatrix} and V2=(11)\vec{V}_2 = \begin{pmatrix} 1 \\ 1 \end{pmatrix} with the coefficients a=2a = -2 and b=1b = 1.

Would you like more details on any part of this process or have any questions?

Here are some related questions:

  1. What is a linear combination of vectors?
  2. How do you solve a system of linear equations?
  3. What is the significance of the coefficients in a linear combination?
  4. How can you determine if a set of vectors is linearly independent?
  5. Can a vector be a linear combination of non-basis vectors?
  6. How does the dimension of a vector space relate to linear combinations?
  7. What is the geometric interpretation of a linear combination of vectors?
  8. What role do linear combinations play in vector spaces and subspaces?

Tip: When solving a system of linear equations, you can use methods like substitution, elimination, or matrix operations such as row reduction to find the solution efficiently.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Vector Spaces
Linear Combinations
System of Linear Equations

Formulas

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Theorems

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Suitable Grade Level

Undergraduate