Math Problem Statement
Show that the function f: [1,4]→R defined by f(x) = x ^ 3 - 3x is an increasing function
Solution
To show that the function is increasing on the interval , we need to examine the behavior of its derivative. A function is increasing on an interval if its derivative is non-negative throughout that interval.
Step 1: Compute the derivative of
The derivative of is:
Step 2: Analyze the sign of
We need to determine where is positive, negative, or zero.
First, let's factor the derivative:
Now, let's check the critical points by setting :
This equation gives two critical points:
However, since the function is defined on the interval , we are only concerned with in this interval.
Step 3: Determine the sign of on the interval
Now, let's examine the sign of on the interval :
- At , .
- For (in particular, for ), both and , so .
Thus, for all , with equality only at .
Conclusion:
Since on , the function is increasing on the interval .
Would you like further clarification on any step or more details?
Here are some related questions for further exploration:
- How do critical points influence the behavior of a function?
- What does it mean for a function to be strictly increasing versus non-decreasing?
- How can the second derivative provide more insights into the nature of a function's increase or decrease?
- What is the role of endpoints when determining if a function is increasing or decreasing on a closed interval?
- Can a function be increasing on an interval but have a flat (zero derivative) point within that interval?
Tip: A derivative being zero at a point does not mean the function decreases or increases—it just indicates a potential critical point (like a local maximum, minimum, or inflection point). Always check the sign of the derivative around critical points!
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Increasing Functions
Formulas
f'(x) = 3x^2 - 3
Theorems
First Derivative Test
Suitable Grade Level
Grades 11-12 or Early College