Math Problem Statement
Let G be a k-connected graph and let v1, v2, . . . , vk be k distinct vertices of G. Let H the graph obtained from G by adding a new vertex w and k new edges joining w and v1, v2, . . . , vk, respectively. Prove that κ(H) = k by using Menger’s theorem and Whitney’s inequalities.
Solution
To prove that the connectivity for the graph obtained from a -connected graph by adding a new vertex and connecting it to distinct vertices , we will use Menger's theorem and Whitney's inequalities.
Definitions and Setup
- A graph is -connected if it has at least vertices, and the removal of fewer than vertices cannot disconnect the graph.
- Menger's theorem states that for any two non-adjacent vertices in a graph, the minimum number of vertices whose removal disconnects these vertices is equal to the maximum number of independent paths between them.
- Whitney's inequality for vertex connectivity states that for any graph , , where is the vertex connectivity and is the minimum degree of .
Proof
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Connectivity of : Since is -connected, it means that for any two vertices in , there are at least vertex-disjoint paths between them. Additionally, the removal of fewer than vertices does not disconnect .
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Construction of : The graph is obtained by adding a new vertex and edges for .
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Minimum Degree in : The minimum degree of is at least , because:
- The new vertex has degree .
- Each of the vertices has its degree increased by 1, making sure their degree is still at least .
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Applying Whitney's Inequality: By Whitney's inequality, . Since , we have:
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Using Menger's Theorem: To show that , we need to demonstrate that for any two vertices in , there are at least vertex-disjoint paths between them.
- Consider any two vertices in that are not . Since is -connected, there are at least vertex-disjoint paths between these two vertices in , and these paths are preserved in .
- Consider and any vertex . There are vertices in that provide disjoint paths, and the direct edge provides the -th path. Therefore, there are vertex-disjoint paths between and .
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Combining Results: Since the conditions of Menger's theorem are satisfied, we conclude that .
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Conclusion: Combining the inequalities and , we have:
Therefore, we have shown that the connectivity of the graph is indeed .
Do you want details or have any questions?
Here are 5 numbered questions you could ask:
- Can you provide an example of constructing from for a specific ?
- How does Menger's theorem help in proving connectivity results?
- What are some applications of Whitney's inequalities in graph theory?
- How would the proof change if we were adding more than edges from to ?
- What are the implications of this result in network design?
Tip: When dealing with graph connectivity problems, leveraging theorems like Menger's and inequalities like Whitney's can simplify the proofs significantly.
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Math Problem Analysis
Mathematical Concepts
Graph Theory
Connectivity
Menger's Theorem
Whitney's Inequality
Formulas
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Theorems
Menger's Theorem
Whitney's Inequality
Suitable Grade Level
Advanced Undergraduate