Math Problem Statement

Prove β prime distribution from β distribution\beta\text{ prime distribution from }\beta\text{ distribution}

Solution

To prove that the transformation Y=X1XY = \frac{X}{1-X} leads from a Beta distribution β1(l,m)\beta_1(l, m) to a Beta prime distribution β2(l,m)\beta_2(l, m), we need to start by looking at the probability density functions (PDFs) of both distributions and perform the appropriate transformation.

1. Beta Distribution β1(l,m)\beta_1(l, m)

The probability density function (PDF) of the Beta distribution Xβ1(l,m)X \sim \beta_1(l, m) is given by:

fX(x)=xl1(1x)m1B(l,m),0<x<1f_X(x) = \frac{x^{l-1}(1-x)^{m-1}}{B(l, m)}, \quad 0 < x < 1

where B(l,m)B(l, m) is the Beta function, defined as:

B(l,m)=01tl1(1t)m1dtB(l, m) = \int_0^1 t^{l-1} (1-t)^{m-1} \, dt

2. Transformation to Beta Prime Distribution

Let Y=X1XY = \frac{X}{1-X}. We need to find the distribution of YY.

First, solve for XX in terms of YY:

X=Y1+YX = \frac{Y}{1 + Y}

Next, we find the derivative of XX with respect to YY:

dXdY=1(1+Y)2\frac{dX}{dY} = \frac{1}{(1+Y)^2}

3. Change of Variables

To find the PDF of YY, we use the change of variables formula:

fY(y)=fX(x)dxdyf_Y(y) = f_X(x) \left| \frac{dx}{dy} \right|

Substitute x=y1+yx = \frac{y}{1+y} and dxdy=1(1+y)2\frac{dx}{dy} = \frac{1}{(1+y)^2}:

fY(y)=fX(y1+y)1(1+y)2f_Y(y) = f_X\left(\frac{y}{1+y}\right) \cdot \frac{1}{(1+y)^2}

Substitute the expression for fX(x)f_X(x):

fY(y)=(y1+y)l1(1y1+y)m1B(l,m)1(1+y)2f_Y(y) = \frac{\left(\frac{y}{1+y}\right)^{l-1}\left(1 - \frac{y}{1+y}\right)^{m-1}}{B(l, m)} \cdot \frac{1}{(1+y)^2}

Simplify the expression inside the PDF:

fY(y)=yl1(1+y)1l(1+y)1mB(l,m)(1+y)2=yl1B(l,m)(1+y)lmf_Y(y) = \frac{y^{l-1}(1+y)^{1-l} (1+y)^{1-m}}{B(l, m) (1+y)^2} = \frac{y^{l-1}}{B(l, m)} \cdot (1+y)^{-l-m}

Thus, the PDF of YY is:

fY(y)=yl1B(l,m)(1+y)lm,y>0f_Y(y) = \frac{y^{l-1}}{B(l, m)} \cdot (1+y)^{-l-m}, \quad y > 0

4. Beta Prime Distribution β2(l,m)\beta_2(l, m)

The PDF of the Beta prime distribution Yβ2(l,m)Y \sim \beta_2(l, m) is:

fY(y)=yl1B(l,m)(1+y)(l+m),y>0f_Y(y) = \frac{y^{l-1}}{B(l, m)} (1+y)^{-(l+m)}, \quad y > 0

Conclusion:

The derived PDF of Y=X1XY = \frac{X}{1-X} exactly matches the PDF of the Beta prime distribution β2(l,m)\beta_2(l, m). Therefore, we have proven that if XX follows a Beta distribution β1(l,m)\beta_1(l, m), then the transformed variable Y=X1XY = \frac{X}{1-X} follows a Beta prime distribution β2(l,m)\beta_2(l, m).

Would you like further explanations or another example?

Follow-up Questions:

  1. How does the transformation impact the moments of the distribution?
  2. Can you derive the cumulative distribution function (CDF) for the Beta prime distribution?
  3. How would the proof change if we considered a different transformation, like Y=1XXY = \frac{1-X}{X}?
  4. What are the special cases of the Beta prime distribution for specific values of ll and mm?
  5. How is the Beta prime distribution used in real-world applications?

Tip:

When working with transformations of random variables, it's essential to carefully consider the domain and ensure that the new PDF is properly normalized across the transformed range.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Beta Distribution
Beta Prime Distribution
Change of Variables

Formulas

PDF of Beta Distribution
PDF of Beta Prime Distribution
Change of Variables Formula

Theorems

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Suitable Grade Level

Advanced Undergraduate