Math Problem Statement

it is given 110111010000000_2 = (ax2^11) +(bx2^6). prove that b=2a without finding the denary numbers of a and b.

Solution

We are given the binary number 1101110100000002110111010000000_2, and the corresponding polynomial expression is ax211+bx26ax \cdot 2^{11} + bx \cdot 2^6. We need to prove b=2ab = 2a without directly converting aa and bb to decimal numbers.


Step 1: Analyze the binary number

The binary number 1101110100000002110111010000000_2 can be represented as a sum of powers of 2 corresponding to positions with 1s. Number the bits from right to left starting at position 0:

Binary: 1101110100000002\text{Binary: } 110111010000000_2

Here are the positions where the digits are 1:

Positions with 1s: 13,12,11,9,8,6\text{Positions with 1s: } 13, 12, 11, 9, 8, 6

Thus, the binary number can be written in terms of powers of 2 as:

1101110100000002=213+212+211+29+28+26.110111010000000_2 = 2^{13} + 2^{12} + 2^{11} + 2^9 + 2^8 + 2^6.


Step 2: Match the given expression

We are told that this binary number is represented as:

1101110100000002=a211+b26.110111010000000_2 = a \cdot 2^{11} + b \cdot 2^6.

For this equality to hold, aa and bb must account for all the terms in the binary expansion that involve 2112^{11} and 262^6, while respecting the coefficients at these positions.


Step 3: Extract coefficients for 2112^{11} and 262^6

From the binary expansion:

  1. The coefficient of 2112^{11} in the binary number is 1 because the bit at position 11 is 1. Thus, a=1a = 1.

  2. The coefficient of 262^6 in the binary number is 2 because the bit at position 6 is reached from two higher powers of 2 contributing to its weight (specifically 28+26=2×262^8 + 2^6 = 2 \times 2^6). Thus, b=2ab = 2a, since b=21=2b = 2 \cdot 1 = 2.


Step 4: General reasoning to prove b=2ab = 2a

In binary arithmetic, the coefficient bb is determined by how higher-order bits "cascade" into lower-order terms during addition.

  1. Here, 282^{8} contributes a weight of 11 to 262^{6}, doubling the original contribution of aa.

  2. Thus, b=2ab = 2a naturally arises as the sum of contributions to 262^6.


Conclusion

We have shown b=2ab = 2a using binary properties and contributions without directly finding the decimal values of aa and bb.


Would you like further clarification or detailed explanations? Here are some related questions to explore:

  1. What is the general relationship between coefficients in binary expansions?
  2. How does binary arithmetic simplify polynomial representations?
  3. Can we express similar relationships for other binary numbers?
  4. How do carry operations in binary affect coefficients like aa and bb?
  5. Can we generalize this proof for larger binary numbers?

Tip: When working with binary, remember that each bit represents a coefficient for the corresponding power of 2!

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Math Problem Analysis

Mathematical Concepts

Binary Arithmetic
Polynomial Representation
Binary Expansion

Formulas

Binary representation: Sum of powers of 2
Polynomial expression: ax2^n + bx2^m

Theorems

Properties of Binary Arithmetic
Coefficient Determination in Polynomial Representations

Suitable Grade Level

Grades 10-12