https://file.aiquickdraw.com/mathbot/file/172677608381355rcod32.jpg

The problem in the image states that the gardener uses 100 mL of water for every 20 pumpkin seeds. It asks how much water the gardener will use for 50 pumpkin seeds, assuming a proportional relationship.

We can solve this using the following proportional relationship:

\[
\frac{100 \, \text{mL}}{20 \, \text{seeds}} = \frac{x \, \text{mL}}{50 \, \text{seeds}}
\]

Where \(x\) is the amount of water needed for 50 seeds. We can solve for \(x\) by cross-multiplying:

\[
100 \times 50 = 20 \times x
\]

\[
5000 = 20x
\]

\[
x = \frac{5000}{20} = 250 \, \text{mL}
\]

Therefore, the gardener will use **250 mL** of water to plant 50 pumpkin seeds.

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:
1. How much water would be required to plant 100 pumpkin seeds?
2. If the gardener had only 300 mL of water, how many seeds could he plant?
3. How can you express the ratio of water to pumpkin seeds as a unit rate?
4. What mathematical operations are commonly used to solve proportional relationships?
5. How does the concept of direct proportionality help in real-life scenarios like gardening?

**Tip:** When solving proportional problems, setting up ratios and cross-multiplying is a powerful tool to find unknown values.

A gardener is planting pumpkin seeds. For every 20 pumpkin seeds planted, he uses 100 mL of water. If this represents a proportional relationship, how many mL of water will the gardener use to plant 50 pumpkin seeds?

Learn how to solve a proportional relationship problem, where a gardener uses 100 mL of water for every 20 pumpkin seeds. Discover how much water is required to plant 50 pumpkin seeds using cross-multiplication and proportionality. Suitable for Grades 6-8 students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation