https://file.aiquickdraw.com/mathbot/file/1727845091202h2wz241d.jpg

The problem in the image asks to set up and solve a proportion to find how much all of the school's cans weigh based on some data. Here’s how to solve it step-by-step.

### Problem:
- Elsie finds that 50 cans weigh 0.8 kg.
- The next day, she counts that her fellow students throw away 1,240 cans each day.

### Objective:
We need to find the total weight of 1,240 cans using the data Elsie gathered.

### Step-by-step solution:
1. **Set up the proportion** based on the information that 50 cans weigh 0.8 kg. Let $ W $ represent the total weight of 1,240 cans.
   
   The proportion is:
   \[
   \frac{50 \, \text{cans}}{0.8 \, \text{kg}} = \frac{1240 \, \text{cans}}{W \, \text{kg}}
   \]

2. **Cross-multiply** to solve for $ W $:
   \[
   50 \times W = 0.8 \times 1240
   \]
   \[
   50W = 992
   \]

3. **Solve for $ W $**:
   \[
   W = \frac{992}{50} = 19.84 \, \text{kg}
   \]

### Conclusion:
The total weight of 1,240 cans is **19.84 kg**.

Would you like more details on any of these steps or have any further questions?

Here are 5 related questions for practice:
1. If 100 cans weigh 1.6 kg, how much would 2,000 cans weigh?
2. If the weight of 1,240 cans is 19.84 kg, how much would 620 cans weigh?
3. How many cans would weigh 10 kg if 50 cans weigh 0.8 kg?
4. If 0.8 kg of cans can be sold for $5, how much money can be earned from 19.84 kg of cans?
5. How many kilograms would 10,000 cans weigh based on the same ratio?

**Tip**: When working with proportions, always remember to maintain the same units across your ratios for consistency!

Elsie is starting a recycling club at her school and wants to use the money earned from recycling cans to buy recycling bins. She finds that 50 cans weigh 0.8 kg, and the school throws away 1,240 cans per day. How much do all of the school's cans weigh?

Learn how to calculate the total weight of recycled cans using proportions. Elsie discovers that 50 cans weigh 0.8 kg, and her school throws away 1,240 cans per day. Solve the problem step-by-step using cross-multiplication.

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