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The task asks to find the proportion of survival times in the sample that are greater than or equal to 20 months based on the given histogram.

From the histogram:

- The bar representing 0–10 months has a frequency of 5.
- The bar representing 10–20 months has a frequency of 8.
- The bar representing 20–30 months has a frequency of 6.
- The bar representing 30–40 months has a frequency of 4.
- The bar representing 40–50 months has a frequency of 1.

The total number of patients is the sum of all the frequencies:  
\[ 5 + 8 + 6 + 4 + 1 = 24 \]

To find the proportion of survival times that are **greater than or equal to 20 months**, we sum the frequencies for the intervals 20–30, 30–40, and 40–50 months:
\[ 6 + 4 + 1 = 11 \]

Thus, the proportion is:
\[
\frac{11}{24} \approx 0.4583
\]

So, the proportion is approximately **0.458**.

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you interpret the heights of bars in a histogram?
2. What does it mean to calculate a proportion in statistics?
3. Why are intervals like 20–30 months considered as "greater than or equal to 20"?
4. How can this histogram be used to estimate other survival time intervals?
5. What are some key differences between histograms and bar charts?

**Tip:** When calculating proportions, ensure that you are accurately summing the appropriate categories from the data source to avoid common mistakes.

Based on the histogram, find the proportion of survival times in the sample that are greater than or equal to 20 months. Write your answer as a decimal, and do not round your answer.

Learn how to calculate the proportion of survival times greater than or equal to 20 months from a histogram showing frequency distribution. The example involves calculating proportions based on intervals in a descriptive statistics context. Suitable for students in Grades 10-12.

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