Math Problem Statement

Prove that the intensity of the radiation is greatest according to the Vienna transition law

Solution

The Wien's displacement law (sometimes referred to as the Vienna transition law) is crucial in understanding the relationship between the temperature of a black body and the wavelength at which its radiation intensity is at its peak. Here's a structured proof based on Planck's law, which describes the intensity of radiation emitted by a black body at a given temperature.

Step 1: Planck's Law for Black Body Radiation

The spectral radiance I(λ,T)I(\lambda, T), which gives the power emitted per unit area per unit wavelength by a black body at temperature TT, is given by Planck's law:

I(λ,T)=2hc2λ51ehcλkT1I(\lambda, T) = \frac{2hc^2}{\lambda^5} \cdot \frac{1}{e^{\frac{hc}{\lambda kT}} - 1}

where:

  • I(λ,T)I(\lambda, T) is the intensity as a function of wavelength λ\lambda and temperature TT,
  • hh is Planck's constant,
  • cc is the speed of light,
  • kk is Boltzmann's constant,
  • λ\lambda is the wavelength,
  • TT is the temperature.

Step 2: Maximizing the Radiation Intensity

To find the wavelength λmax\lambda_{\text{max}} at which the radiation intensity is greatest, we need to maximize the function I(λ,T)I(\lambda, T) with respect to λ\lambda.

That is, we need to solve:

dI(λ,T)dλ=0\frac{dI(\lambda, T)}{d\lambda} = 0

This process requires differentiating Planck's law with respect to λ\lambda. The derivative involves applying the product and chain rules, making this a fairly complex expression.

Step 3: Simplifying the Equation

To simplify the calculation, we can introduce a substitution: x=hcλkTx = \frac{hc}{\lambda kT}

This substitution simplifies the expression for I(λ,T)I(\lambda, T) and allows us to rewrite Planck's law in terms of xx and λ\lambda. After differentiating and simplifying, we get the following transcendental equation:

5(1ex)x=05(1 - e^{-x}) - x = 0

Step 4: Solving the Equation Numerically

The above equation does not have an analytical solution, but it can be solved numerically. The solution for xx is approximately:

x4.9651x \approx 4.9651

Step 5: Apply the Substitution Back

Using the substitution x=hcλmaxkTx = \frac{hc}{\lambda_{\text{max}} kT}, we can now solve for λmax\lambda_{\text{max}}:

λmax=hc4.9651kT\lambda_{\text{max}} = \frac{hc}{4.9651 kT}

Step 6: Wien's Displacement Law

Finally, this result gives us Wien's displacement law:

λmaxT=hc4.9651k2.898×103mK\lambda_{\text{max}} T = \frac{hc}{4.9651 k} \approx 2.898 \times 10^{-3} \, \text{m} \cdot \text{K}

This shows that the wavelength λmax\lambda_{\text{max}} at which the intensity of the radiation is greatest is inversely proportional to the temperature TT of the black body.

Conclusion

The intensity of radiation is greatest at the wavelength λmax\lambda_{\text{max}}, which is inversely proportional to the temperature of the black body, as described by Wien's displacement law. This law is a result of differentiating and maximizing Planck's radiation law.


Do you need further details or have any questions? Here are five related questions that extend this information:

  1. How does the intensity of radiation change with temperature at a fixed wavelength?
  2. Can Wien's displacement law be applied to non-black bodies?
  3. What are the physical implications of the peak wavelength shifting with temperature?
  4. How does Planck's law relate to the Stefan-Boltzmann law?
  5. What are the limits of applicability for Wien's displacement law?

Tip: The Wien’s displacement law helps in determining the temperature of stars by observing their peak wavelength of emitted radiation.

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Math Problem Analysis

Mathematical Concepts

Black Body Radiation
Planck's Law
Wien's Displacement Law
Calculus (Differentiation)

Formulas

I(λ, T) = (2hc^2 / λ^5) / (e^(hc/λkT) - 1)
λ_max T = hc / (4.9651 k) ≈ 2.898 × 10^-3 m·K

Theorems

Wien's Displacement Law
Planck's Radiation Law

Suitable Grade Level

Undergraduate (Physics/Math Major)