Math Problem Statement

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that the highest bid in excess of $10,000 will be accepted. Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,000 and $15,000.

(a) Suppose you bid $12,000. What is the probability that your bid will be accepted? If required, round your answer to two decimal places. .40

(b) Suppose you bid $14,000. What is the probability that your bid will be accepted? If required, round your answer to two decimal places. .80

(c) What amount should you bid to maximize the probability that you get the property?

Solution

To solve these questions, let’s analyze the competitor’s bid xx, which is uniformly distributed between $10,000 and $15,000.

Since xx is uniformly distributed on [10,000,15,000][10,000, 15,000], the probability density function (pdf) is: f(x)=115,00010,000=15,000=0.0002f(x) = \frac{1}{15,000 - 10,000} = \frac{1}{5,000} = 0.0002

Given that the highest bid wins, we need to calculate the probability that your bid BB is greater than xx, i.e., P(B>x)P(B > x), based on different values for BB.

Part (a): Probability of Bid $12,000$ Being Accepted

If you bid $12,000$, we want the probability that xx (the competitor's bid) is less than $12,000$: P(x<12,000)=10,00012,000f(x)dxP(x < 12,000) = \int_{10,000}^{12,000} f(x) \, dx

Since f(x)=0.0002f(x) = 0.0002: P(x<12,000)=(12,00010,000)0.0002=2,0000.0002=0.40P(x < 12,000) = (12,000 - 10,000) \cdot 0.0002 = 2,000 \cdot 0.0002 = 0.40

So, if you bid $12,000$, the probability that your bid will be accepted is 0.40.

Part (b): Probability of Bid $14,000$ Being Accepted

If you bid $14,000$, we want the probability that xx is less than $14,000$: P(x<14,000)=10,00014,000f(x)dxP(x < 14,000) = \int_{10,000}^{14,000} f(x) \, dx

P(x<14,000)=(14,00010,000)0.0002=4,0000.0002=0.80P(x < 14,000) = (14,000 - 10,000) \cdot 0.0002 = 4,000 \cdot 0.0002 = 0.80

Thus, if you bid $14,000$, the probability that your bid will be accepted is 0.80.

Part (c): Optimal Bid to Maximize Probability

To maximize the probability of winning, you should bid as close as possible to $15,000, but any amount up to $15,000 would maximize your probability, as P(x<B)1P(x < B) \to 1 as B15,000B \to 15,000. Therefore, the optimal bid to maximize the probability of acceptance is just slightly below $15,000.

In summary:

  • (a) The probability your bid of $12,000 will be accepted: 0.40
  • (b) The probability your bid of $14,000 will be accepted: 0.80
  • (c) To maximize the probability of acceptance, you should bid slightly below $15,000.

Would you like further details on any part?

Here are some related questions to explore:

  1. What would the probability be if you bid $13,000?
  2. How does the probability change if the competitor's bid distribution changes?
  3. What if the competitor's bid range were increased to $10,000 to $20,000?
  4. How does this scenario change if there are multiple competitors?
  5. What if the lowest bid were accepted instead of the highest?

Tip: In uniform distribution problems, knowing the range can simplify the calculations significantly, as probabilities are linear over intervals.

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Math Problem Analysis

Mathematical Concepts

Probability
Uniform Distribution
Expected Value

Formulas

Probability density function for uniform distribution: f(x) = 1 / (b - a) where [a, b] is the interval
P(X < B) for uniform distribution on interval [a, b] = (B - a) / (b - a)

Theorems

Uniform Distribution Properties

Suitable Grade Level

Undergraduate Level