Math Problem Statement

Supposed to die one red one green are rolled consider the following events. The red dye shows two the numbers add to five at least one of the numbers is two. The numbers do not add to nine express the given event in symbolic form and how many elements does it contain.

Solution

Let's define the problem step by step. We are rolling two dice: one red die and one green die. Let’s denote the outcome of the red die as RR and the outcome of the green die as GG, where RR and GG are values from the set {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\}.

Event Descriptions:

  1. The red die shows two: This event can be written as R=2R = 2.
  2. The numbers add to five: This event can be written as R+G=5R + G = 5.
  3. At least one of the numbers is two: This event can be written as R=2R = 2 or G=2G = 2, i.e., R=2G=2R = 2 \lor G = 2.
  4. The numbers do not add to nine: This event can be written as R+G9R + G \neq 9.

Expressing Each Event in Symbolic Form:

  • Red die shows two: R=2R = 2
  • Numbers add to five: R+G=5R + G = 5
  • At least one of the numbers is two: R=2G=2R = 2 \lor G = 2
  • Numbers do not add to nine: R+G9R + G \neq 9

Finding How Many Elements Each Event Contains:

  1. The red die shows two: The possible values for GG can be {1,2,3,4,5,6}\{1, 2, 3, 4, 5, 6\} (since R=2R = 2).

    • There are 6 possible outcomes for GG, so this event contains 6 elements.
  2. The numbers add to five: The pairs that satisfy R+G=5R + G = 5 are:

    • (R,G)=(1,4),(2,3),(3,2),(4,1)(R, G) = (1, 4), (2, 3), (3, 2), (4, 1)
    • There are 4 pairs, so this event contains 4 elements.
  3. At least one of the numbers is two: The possible pairs are:

    • (R,G)=(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)(R, G) = (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (if R=2R = 2)
    • (R,G)=(1,2),(3,2),(4,2),(5,2),(6,2)(R, G) = (1, 2), (3, 2), (4, 2), (5, 2), (6, 2) (if G=2G = 2)
    • These events together account for 11 distinct pairs (since (2,2)(2, 2) is counted only once).
    • This event contains 11 elements.
  4. The numbers do not add to nine: The pairs where R+G=9R + G = 9 are:

    • (R,G)=(3,6),(4,5),(5,4),(6,3)(R, G) = (3, 6), (4, 5), (5, 4), (6, 3)
    • There are 4 pairs, so the complementary event R+G9R + G \neq 9 contains 6×64=364=326 \times 6 - 4 = 36 - 4 = 32 elements.

Summary:

  • The red die shows two: 6 elements.
  • The numbers add to five: 4 elements.
  • At least one of the numbers is two: 11 elements.
  • The numbers do not add to nine: 32 elements.

Would you like more details or clarifications on any of these?

Here are 5 related questions to explore this concept further:

  1. How many outcomes are there in total when rolling two six-sided dice?
  2. What is the probability that the numbers add up to five?
  3. What is the probability that at least one die shows two?
  4. What is the probability that the sum of the dice is not nine?
  5. How would the result change if the dice had more than six sides?

Tip: When working with dice, listing out all possible outcomes helps to systematically approach problems involving sums or specific number conditions.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Probability
Set Theory
Combinatorics

Formulas

Event representation in set theory: R = 2, R + G = 5, R + G ≠ 9
Basic counting principles

Theorems

Addition Rule of Probability
Complement Rule

Suitable Grade Level

Grades 9-12