In this question, we are asked to find the probability of getting a sum greater than 10 when two dice are rolled together.

Step-by-step solution:

1. Total outcomes when two dice are rolled:
   When rolling two dice, each die has 6 faces, so the total number of possible outcomes is: $6 \times 6 = 36$

2. Favorable outcomes:
   We need to find the outcomes where the sum of the dice is greater than 10. The sums greater than 10 can be 11 or 12:

   • Sum = 11: The pairs are (5,6) and (6,5). Hence, there are 2 outcomes.
   • Sum = 12: The only pair is (6,6). Hence, there is 1 outcome.

   Therefore, the total number of favorable outcomes is: $2 \, (\text{for sum } 11) + 1 \, (\text{for sum } 12) = 3$

3. Probability:
   The probability is the ratio of favorable outcomes to total outcomes: $P(\text{sum} > 10) = \frac{3}{36} = \frac{1}{12}$

Thus, the correct answer is (c) 1/12.

Do you want further explanation on any step, or have any questions about probabilities with dice rolls?

Related Questions:

1. How many total outcomes are possible when rolling two dice?
2. How do you calculate probabilities in dice games with multiple dice?
3. What is the probability of getting a sum less than 5 when two dice are rolled?
4. How can we calculate the probability of rolling doubles with two dice?
5. What is the probability of getting a sum equal to 7 when two dice are rolled?

Tip:

When calculating probabilities for dice rolls, always remember to count all possible outcomes (which is the total number of combinations) and then determine how many of those outcomes are favorable for the event you are interested in.