The problem in the image asks about the probability that two people (Rebecka and Aaron) each select a poodle at random without replacement from a group of 11 puppies. There are 2 poodles, 5 terriers, and 4 retrievers in the group.

To solve the problem, let's calculate the probability step by step:

1. Total Puppies: 11 puppies in total.
2. First Selection (Rebecka):
   • The probability that Rebecka selects a poodle is the ratio of poodles to the total puppies: $P(\text{Rebecka selects poodle}) = \frac{2}{11}$
3. Second Selection (Aaron):
   • After Rebecka picks a poodle, only 10 puppies remain, and there is now only 1 poodle left. $P(\text{Aaron selects poodle}) = \frac{1}{10}$
4. Combined Probability: Since both events are independent and without replacement, we multiply the probabilities: $P(\text{Both select poodle}) = \frac{2}{11} \times \frac{1}{10} = \frac{2}{110} = \frac{1}{55}$

So, the probability that both Rebecka and Aaron select a poodle is $\frac{1}{55}$.

Would you like more details or have any questions about this?

Here are five related questions you could explore:

1. What is the probability that both Rebecka and Aaron select terriers?
2. How does the probability change if there were 3 poodles instead of 2?
3. What is the probability that neither of them selects a retriever?
4. What if there were replacement—how would the probability change?
5. What is the probability that at least one of them selects a poodle?

Tip: Always double-check if the scenario involves replacement or no replacement, as it significantly affects the probability calculation.