We can solve this probability problem by determining the favorable outcome (i.e., a male with no credit cards) and the total number of individuals in the group.

Step 1: Total Number of Individuals

To find the total number of individuals, sum the values from all categories:

• Males:

  • Zero cards: 9
  • One card: 11
  • Two or more cards: 3

  Total males = $9 + 11 + 3 = 23$

• Females:

  • Zero cards: 4
  • One card: 10
  • Two or more cards: 20

  Total females = $4 + 10 + 20 = 34$

The total number of individuals is: $23 + 34 = 57$

Step 2: Favorable Outcome (Male with Zero Credit Cards)

The number of males with no credit cards is 9.

Step 3: Probability Calculation

The probability is given by the ratio of favorable outcomes to the total number of outcomes: $P(\text{Male with zero credit cards}) = \frac{9}{57}$

Simplifying the fraction: $P(\text{Male with zero credit cards}) = \frac{1}{6} \approx 0.17$

Thus, the probability that a randomly chosen person is a male with no credit cards is 0.17.

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Would you like further details or have any other questions?

Related Questions:

1. What is the probability of selecting a female with one credit card?
2. What is the probability of selecting a person with two or more credit cards?
3. What is the probability of selecting a male with one credit card?
4. What is the probability of selecting a person with no credit cards?
5. What is the probability of selecting a female with two or more credit cards?

Tip: When calculating probabilities, always ensure you correctly identify the total number of possible outcomes for accuracy.