The image shows a probability question based on a table. Let me extract and analyze the content to solve the problem.

Table Data (Assumed from Image):

Gender	Total	Right Handed	Left Handed	Ambidextrous
Male	20	16 (80%)	3 (15%)	1 (5%)
Female	20	18 (90%)	2 (10%)	0 (0%)

Question:

The problem asks to find the probability that a randomly chosen person is either male or right-handed.

Solution:

Step 1: Determine the total number of people.

Total people = Males + Females = 20 (Male) + 20 (Female) = 40 people.

Step 2: Calculate the number of males.

Number of males = 20.

Step 3: Calculate the number of right-handed people.

• Right-handed males: 16
• Right-handed females: 18 Total right-handed = 16 + 18 = 34.

Step 4: Calculate the probability of selecting a male or right-handed person.

Since there might be overlap (male and right-handed), we use the formula for the union of two events: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$

Where:

• $P(A)$ is the probability of choosing a male.
• $P(B)$ is the probability of choosing a right-handed person.
• $P(A \cap B)$ is the probability of choosing a male who is also right-handed.

$P(A) = \frac{20}{40} = 0.5$ $P(B) = \frac{34}{40} = 0.85$ $P(A \cap B) = \frac{16}{40} = 0.4$

Now, applying the formula: $P(A \cup B) = 0.5 + 0.85 - 0.4 = 0.95$

Final Answer:

The probability that a randomly chosen person is either male or right-handed is 0.95.

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Would you like further details or have any questions?

Relative Questions:

1. How do we calculate the probability of mutually exclusive events?
2. What is the significance of subtracting $P(A \cap B)$ in the formula?
3. How would the probability change if the table data were altered slightly?
4. How do we calculate conditional probability from this table?
5. What is the complement rule in probability, and how does it apply here?

Tip:

When dealing with "or" probability scenarios involving two characteristics, always consider the possibility of overlap (i.e., individuals who possess both characteristics).