Math Problem Statement

A group of people were asked if they had run a red light in the last year. The number of people that responded yes is 164 and no is 351. Find the probability that if a person is chosen at random, he/she has run a red light in the last year. Round to two decimal places.

Solution

To find the probability that a randomly chosen person has run a red light in the last year, we use the formula for probability:

P(run a red light)=number of people who responded yestotal number of people surveyedP(\text{run a red light}) = \frac{\text{number of people who responded yes}}{\text{total number of people surveyed}}

Here, the number of people who responded "yes" is 164, and the total number of people surveyed is the sum of those who said "yes" and those who said "no":

Total people surveyed=164+351=515\text{Total people surveyed} = 164 + 351 = 515

Thus, the probability is:

P(run a red light)=1645150.3184P(\text{run a red light}) = \frac{164}{515} \approx 0.3184

Rounding to two decimal places:

P(run a red light)0.32P(\text{run a red light}) \approx 0.32

So, the probability is 0.32.

Would you like more details or have any questions?

Here are five related questions:

  1. What is the probability that a person chosen at random has not run a red light?
  2. How would the probability change if 50 more people responded "yes"?
  3. If you repeated this survey with twice as many people, what would you expect the probabilities to be?
  4. Can you express the probability as a percentage instead of a decimal?
  5. How could you use these probabilities to estimate how many people in a larger population might have run a red light?

Tip: Probabilities always range between 0 and 1, and a probability closer to 1 means a higher likelihood of the event occurring.

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Math Problem Analysis

Mathematical Concepts

Probability
Statistics

Formulas

P(event) = number of favorable outcomes / total number of outcomes

Theorems

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Suitable Grade Level

Grades 6-8