Math Problem Statement
A box contains 6 black balls and 4 green balls. Three balls were drawn in successive with replacement. What is the probability of getting three the same color?
Solution
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Math Problem Analysis
Mathematical Concepts
Probability
Independent Events
Multiplication Rule of Probability
Formulas
P(Black) = 6/10
P(Green) = 4/10
P(Three Black) = P(Black) × P(Black) × P(Black)
P(Three Green) = P(Green) × P(Green) × P(Green)
P(Three Same Color) = P(Three Black) + P(Three Green)
Theorems
Multiplication rule of independent events
Suitable Grade Level
Grades 8-10
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