Giving a test to a group of students, the grades and gender are summarized below

A	B	C	Total
Male	10	2	18	30
Female	15	5	9	29
Total	25	7	27	59


If one student is chosen at random,

Find the probability that the student was male OR got an "A". (Enter answer as a fraction or to 4 decimal places.)

We are asked to find the probability that a student chosen at random is either male **OR** got an "A". To solve this, we'll use the formula for the probability of the union of two events:

\[
P(\text{Male OR A}) = P(\text{Male}) + P(\text{A}) - P(\text{Male AND A})
\]

Where:

- \( P(\text{Male}) \) is the probability that the student is male.
- \( P(\text{A}) \) is the probability that the student received an "A".
- \( P(\text{Male AND A}) \) is the probability that the student is male and received an "A".

### Step 1: Find \( P(\text{Male}) \)
The total number of males is 30 out of 59 students, so:

\[
P(\text{Male}) = \frac{30}{59}
\]

### Step 2: Find \( P(\text{A}) \)
The total number of students who received an "A" is 25 out of 59 students, so:

\[
P(\text{A}) = \frac{25}{59}
\]

### Step 3: Find \( P(\text{Male AND A}) \)
The number of males who received an "A" is 10, so:

\[
P(\text{Male AND A}) = \frac{10}{59}
\]

### Step 4: Apply the formula
Now, substitute the values into the formula:

\[
P(\text{Male OR A}) = \frac{30}{59} + \frac{25}{59} - \frac{10}{59}
\]

\[
P(\text{Male OR A}) = \frac{30 + 25 - 10}{59} = \frac{45}{59}
\]

Thus, the probability that a student chosen at random is either male or received an "A" is:

\[
P(\text{Male OR A}) = \frac{45}{59}
\]

This is the exact probability. To express it as a decimal, it is approximately:

\[
P(\text{Male OR A}) \approx 0.7627
\]

### Final Answer:
The probability that a student chosen at random is either male or got an "A" is \( \frac{45}{59} \) or approximately 0.7627.

---

Would you like more details or have any questions? Here are five related questions you might consider:

1. What is the probability that a student chosen at random is female?
2. What is the probability that a student received a "B" grade?
3. How would the probability change if the number of males who received an "A" increased by 5?
4. What is the probability that a student is either female or received a "C"?
5. What is the probability that a student received an "A" and is female?

**Tip:** When dealing with probabilities involving "or", remember to subtract the overlap (intersection) to avoid double-counting.

Giving a test to a group of students, the grades and gender are summarized below:

A	B	C	Total
Male	10	2	18	30
Female	15	5	9	29
Total	25	7	27	59

If one student is chosen at random, find the probability that the student was male OR got an "A". (Enter answer as a fraction or to 4 decimal places.)

Explore the probability that a student chosen at random is either male or received an A grade from a group of 59 students. The solution covers key probability concepts, including the union of events and the Inclusion-Exclusion Principle. Suitable for students in Grades 9-12.

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