Math Problem Statement

Question content area top Part 1 Assume that when human resource managers are randomly​ selected, 57​% say job applicants should follow up within two weeks. If 6 human resource managers are randomly​ selected, find the probability that at least 2 of them say job applicants should follow up within two weeks. Question content area bottom Part 1 The probability is    enter your response here. ​(Round to four decimal places as​ needed.)

Solution

This problem can be solved using the binomial probability formula, which is used when there are only two outcomes: success or failure. In this case, success is defined as an HR manager saying that job applicants should follow up within two weeks, and failure is the opposite.

Step-by-Step Solution

Step 1: Define the parameters for the binomial distribution.

  • The probability of success, p=0.57p = 0.57 (57%).
  • The probability of failure, q=1p=0.43q = 1 - p = 0.43.
  • The number of trials (HR managers), n=6n = 6.
  • The minimum number of successes (at least 2 managers say follow up), x2x \geq 2.

Step 2: Use the complement rule to find the probability.

It’s easier to calculate the probability of fewer than 2 successes, and then subtract from 1 to find the probability of at least 2 successes:

P(at least 2 successes)=1P(0 or 1 success)P(\text{at least 2 successes}) = 1 - P(\text{0 or 1 success})

This means we need to find the probabilities for:

  1. 0 successes
  2. 1 success

Step 3: Use the binomial probability formula.

The binomial probability formula is:

P(X=k)=(nk)pkqnkP(X = k) = \binom{n}{k} p^k q^{n-k}

Where:

  • (nk)\binom{n}{k} is the binomial coefficient (combinations),
  • pp is the probability of success,
  • qq is the probability of failure,
  • nn is the number of trials,
  • kk is the number of successes.

Now calculate for:

  1. P(X=0)P(X = 0)
  2. P(X=1)P(X = 1)

Step 4: Calculate probabilities.

Let's calculate P(X=0)P(X = 0) and P(X=1)P(X = 1), then find P(X2)P(X \geq 2).

I'll compute these probabilities now.The probability that at least 2 of the 6 randomly selected human resource managers say job applicants should follow up within two weeks is 0.9434.

Would you like further details or have any other questions?

Here are 5 related questions to explore:

  1. What is the probability that exactly 2 managers say follow up within two weeks?
  2. How would the result change if the probability of success were different, say 70%?
  3. What is the probability that none of the managers recommend following up?
  4. How is the binomial distribution different from a normal distribution?
  5. How can this method be applied to larger populations, like 100 HR managers?

Tip: The complement rule is often useful when it's easier to calculate the opposite scenario.

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Math Problem Analysis

Mathematical Concepts

Probability
Binomial Distribution
Complement Rule

Formulas

Binomial probability formula: P(X = k) = C(n, k) * p^k * (1 - p)^(n-k)
Complement rule: P(at least 2 successes) = 1 - P(0 or 1 success)

Theorems

Binomial Theorem

Suitable Grade Level

Grades 10-12