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The problem asks to find the probability that a randomly chosen student is both female and received a "B" grade.

### Steps to solve:
1. From the table, the number of female students who got a "B" is **8**.
2. The total number of students is **100** (sum of all the totals in the table).

### Probability Formula:
The probability of an event is calculated as:

\[
P(\text{Female and B}) = \frac{\text{Number of female students who got a "B"}}{\text{Total number of students}}
\]

Substitute the values:

\[
P(\text{Female and B}) = \frac{8}{100} = 0.08
\]

So, the probability is **0.08** or **8%**.

Would you like a detailed breakdown or have any further questions?

Here are some related questions you can explore:
1. What is the probability that a student is male and got a "C"?
2. What is the probability that a randomly chosen student is non-binary?
3. What is the probability that a student got an "A" grade, regardless of gender?
4. What is the probability that a randomly chosen student is female?
5. What is the probability that a student got a "B" grade, regardless of gender?

**Tip:** Probabilities always add up to 1 when considering all possible outcomes, so they can be helpful to double-check your work.

Find the probability that a randomly chosen student was female AND got a 'B'.

Learn how to calculate the probability of a female student getting a 'B' grade from a group of students with detailed analysis. This problem covers essential probability concepts suitable for students in Grades 6-8.

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