To solve this probability question, let's break it down step-by-step.

Information Given:

1. Cards available: 7, 8, 9
2. Two draws are made without replacement.
3. We are asked for the probability of:
   • Drawing an even number on the first draw.
   • Drawing another even number on the second draw.

Step-by-Step Solution:

1. Identify even numbers: Among the numbers 7, 8, and 9, only 8 is even.

2. First Draw Probability (Even Number):

   • There is 1 even card (8) out of 3 cards.
   • Probability of picking an even number (8) on the first draw = $\frac{1}{3}$.

3. Second Draw Probability (Even Number):

   • Since the draws are without replacement, if we pick 8 on the first draw, it won't be available for the second draw.
   • This leaves us with only two cards: 7 and 9, which are both odd.
   • Probability of picking an even number on the second draw = 0 (since no even cards are left).

Final Probability Calculation:

Since the probability of picking an even number on the second draw is 0, the overall probability of picking an even number and then another even number is also 0%.

Answer:

The probability of picking an even number followed by another even number is: \textbf{0%}

Would you like a further breakdown, or do you have any questions?

Here are five additional related questions:

1. What is the probability of picking an odd number first and then another odd number?
2. How would the probability change if the cards were replaced after each draw?
3. What is the probability of picking an even number on the first draw regardless of the second?
4. How does drawing without replacement affect the probability compared to drawing with replacement?
5. If we added an additional card with an even number, how would that affect the probability?

Tip: Remember that without replacement reduces the total number of options for the second draw, which can make it impossible to meet certain conditions.